(50-x):4=0.8:2分之1
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方程化简:(17-20X)/3=(10X-10)/7方程两边都乘以21得:7(17-20X)=3(10X-10)119-140X=30X-30170X=149X=149/170.再问:10不是分子中的
2x+3x+4x=189x=18x=213x-15x+x=-3-x=-3x=32.5y+10y-6y=15-21.56.5y=-6.5y=-12分1b-3分之2b+b=2分之3x6-15/6b=8b=
(3x+2)^2=4(x-3)^2(3x+2)^2-4(x-3)^2=0(3x+2+2x-6)(3x+2-2x+6)=0(5x-4)(x+8)=0x=4/5或x=-8
2-(X-1)/3=(1-X)/2+3-X(7-X)/3=(7-3X)/214-2X=21-9X7X=7X=1把X=1代入方程得4-K/3=0K=12
∵5x(x+2)=4x+8,∴5x(x+2)-4(x+2)=0,∴(x+2)(5x-4)=0,∴x+2=0或5x-4=0,解得:x1=-2,x2=45.
[(x+2)+1]/(x+2)-[(x+1)+1]/(x+1)=[(x+4)+1]/(x+4)-[(x+3)+1]/(x+3)1+1/(x+2)-1-1/(x+1)=1+1/(x+4)-1-1/(x+
5x(3x+2)=6x+45x(3x+2)=2(3x+2)5x(3x+2)-2(3x+2)=0(5x-2)(3x+2)=0x1=2/5x2=-2/3
4x^2-(x-1)^2=0[2x-(x-1)][2x+(x-1)]=0(2x-x+1)(2x+x-1)=0(x+1)(3x-1)=0x=-1或x=1/3
再答:看看可以不再答:看看可以不再问:嗯,谢谢再答:不会了来问我啊,当年哦高考考了138
移项4x(2x+1)-3(2x+1)=0提取公因式(2x+1)(4x-3)=0
3/4:x=1/8:6/51/8x=3/4×6/51/8x=9/10x=72/10
平方差[(x-4)+(5-2x)][(x-4)-(5-2x)]=0(-x+1)(3x-9)=03(x-1)(x-3)=0x=1,x=3
x-4=(x-4)^2,(x-4)^2-(x-4)=0,(x-4)(x-4-1)=0,x=4或x=5(5x-1)(2x+4)=3x+610x²+20x-2x-4-3x-6=010x²
7X(2X-3)=4(3-2X).7x(2x-3)+4(2x-3)=0(7x+4)(2x-3)=0x1=-4/7x2=3/2在右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】了.如还有新的
(2x+3)²-3(2x+3)-4=0(2x+3-4)(2x+3+1)=0(2x-1)(2x+4)=02x-1=0或2x+4=0x1=1/2x2=-2【俊狼猎英】团队为您解答再问:为什么要把
(2x-1)(2x-1)=0再答:x=1/2
移项4x²-1=0(2x+1)(2x-1)=0x=-1/2,x=1/2
(x-4)^2=(5-2x)^2(x-4)^2-(5-2x)^2=0(x-4+5-2x)(x-4-5+2x)=0(1-x)(3x-9)=0x=1或x=3