乙酸与碳酸钙反应方程式
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 14:07:50
HOCH2CHOHCH2OH+3CH3COOH→H3COOCCH2CH(OOCCH3)CH2OCOCH3+3H2O(条件应为可逆、加热、浓硫酸)
2CH3COOH+2NA=2CH3COONA+H2(H2打向上箭头)是这个吗?以前高中学的,记不太得了
CH3COOH+HOCH2CH3=CH3COOCH2CH3,醇与酸反应脱去一个水
乙酸少量CH3COOH+Na2CO3=CH3COONa+NaHCO3乙酸过量Na2CO3+2CH3COOH==2CH3COONa+H2O+CO2↑再问:谢谢!那么与NaHCO3反应呢再答:CH3COO
2Na+2HAc=2NaAc+H2↑
2CH3COOH+CaCO3=(CH3COO)2Ca+CO2↑+H2O
CH3COOH+NaOH=CH3COONa+H2O
CO32-+CH3CO2H=2CO2CH3-+CO2+H2O
反应得到乙酸钙钙和水以及二氧化碳!
2CH3COONa+H2SO4=Na2SO4+2CH3COOH
酯化反应,CH3COOH+HOCH(CH3)2==H+==CH3COOCH(CH3)2
足量乙酸,所以乙二醇的两个羟基都发生酯化反应.方程式:HOCH2-CH2OH+2CH3COOH--浓硫酸,△-->CH3COOCH2-CH2OOC-CH3+2H2O
CH3COOH+NaHCO3==H2O+CO2↑+CH3COONa2CH3COOH+Na2CO3==H2O+CO2↑+2CH3COONa
CH3COOH+HCO3-===CH3COO-+H2O+CO2↑
CH3COOH+CH3CH(OH)CH3--浓硫酸,△-->CH3COOCH(CH3)2+H2O
NaHCO3+CH3COOH=CH3COONa+H2O+CO2(气体)
碱石灰,CaO和NaOH混合物.反应:2CH3COOH+CaO=(CH3COO)2Ca+H2OCH3COOH+NaOH=CH3COONa+H2O产物是乙酸钙、乙酸钠
C6H12O6(葡萄糖)+6CH3COOH→CH3CO-OCH2-CHO(CH3CO)-CHO(CH3CO)-CHO(CH3CO)-CHO(CH3CO)-CH2O-OCH3+6H2O条件:浓硫酸,加热
CH3COOH(乙酸)+C2H5OH(乙醇)——CH3COOC2H5(乙酸乙酯)+H20条件是(浓硫酸、170度)
caco3+2HCL=CACL2+H2O+CO2