(y-5)² (10-x)²=5²,

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 14:44:12
(y-5)² (10-x)²=5²,
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3

x-y/7-x+y/10=1/2两边乘7010x-10y-7x-7y=353x-17y=35(1)2(x-y)+5(x+y)=32x-2y+5x+5y=37x+3y=3(2)(2)*3-(1)*79y

(7x-10y)-(-10y-5x)=?

(7x-10y)-(-10y-5x)=7x-10y+10y+5x=12x再问:7x-10y+10y+5x似乎等于2x+10y再答:-10y+10y=0

已知:丨2x+y-3丨+根号下(x-3y-5)²=0,则x²=?

解题思路:根据非负数的行政列出方程求出x,y的值即可求出x²的值解题过程:

已知x+y=10,求[(x+y)^2-(x-y)^2-2y(x-y)]÷5y的值

[(x+y)²-(x-y)²-2y(x-y)]÷5y=[X²+2XY+Y²-X²+2XY-Y²-2XY+2Y²]÷5Y=[2Y(X

3x+2y=6 ,5x+6y=10那么x+y=?

3x+2y=6,5x+6y=10两个式子相加,得8x+8y=16x+y=23x^2-4x+6=12,3x^2-4x=6则x^2-(4x+2)/3=1/3(3x^2-4x-2)=1/3(6-2)=4/3

已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0

很多数学符号,还是写出来方便.

若7x+10y分之5x+y=1/2,则x/y=

十字相乘下.10x+2y=7x+10y3x=7yx/y=7/3

x+y=5; x^y+y^x=17

X=2,Y=3或X=3,Y=2

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

已知,x²-4x+9y²+6y+5=0,求x+3y的值

解题思路:对于这种等式一定可以化成平方相加的形式,这里面要使用到完全平方公式。解题过程:

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

2/(x+y)+5/(x-y)=189/(x+y)-10/(y-x)=66设x+y=a,x-y=b,原方程化为2/a+5/b=18-----1(1)9/a+10/b=66-------(2)(2)-(

若x和y互为相反数,则3x-10+3y+y/5x=

x+y=0x=-yx/y=y/x=-13x-10+3y+y/5x=3(x+y)-10+y/5x=0-10-1/5=-10.2

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

另a=1/(x+y),b=1/(x-y);则2a+5b=18;9a+10b=66;解得a=6,b=6/5;即       &nbs

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

解方程组:(0.2x+0.1y)/2- (4x-y)/10=(x-y)/5+ (3x+0.5y)/30 (3x+2y-1

(0.2x+0.1y)/2-(4x-y)/10=(x-y)/5+(3x+0.5y)/30①(3x+2y-1)/8=3-(0.8x-5y)/41②①两边同时乘以60得(6x+3y)-(24x-6y)=(

已知x²+9y²-4x+6y+5=0,求x²y³的值

解题思路:先利用完全平方公式求出x、y的值,再代入求出代数式的值。解题过程:

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-