函数y=2-4-x²开根号求值域-搜答案-百度作业网

解y=3分之√3吗?原式=(x²-y²)-(2xy)(2x²-4y²)/(2xy)=x²-y²-2x²+4y²=3y&#

(x-y)分之(x²+y²)+(y-x)分之(2x-y),其中x=3+√2,y=3-√2=(x²+y²)/(x-y)-(2x-y)/(x-y)=(x²

xy^3÷(-xy)+(x+2y)(x-2y)=-y^2+x^2-4y^2=x^2-5y^2=2-5=-3再问：不好意思啊！题目......再答：题目怎么了，不影响结果啊。平方还是正的

x=4,y=1/9所以√x=2√y=1/3原式=4*(1/2)-2/3-9*y√y=2-2/3-1/3=1

(x-y+x+y)/(x^2-y^2)*((x-y)^2/2x)=2x/(x-y)(x+y)*((x-y)^2/2x)=(x-y)/(x+y)x=根号3,y=负根号2原式=（根号3+根号2）/（根号3

[1/x-y)-1/(x+y)）÷2y/(x平方+2xy+y平方)=(x+y-x+y)/(x-y)(x+y)÷2y/(x+y)²=(x+y)/(x-y)x=根号3+2,y=根号3=(√3+2

先求定义域-x2+4x>=0则0

原式=（x²-y²）/(x-y)=(x+y)（x-y)/(x-y)=x+y其他的自己带入即可

√x^-2xy+y^2+x^2-6xy+9y^2/x-3y=√(x-y)^2+(x-3y)^2/x-3y由于y>x=y-x+x-3y=-2y=-2√5

(x^2y-4^y3^/x^2+4xy+4y^2)·(4xy/x-2y+x),其中x=根号2-1,y=根号2+1=(x²y-4y³)/(x+2y)²*(4xy+x

原式=[(√x-√y)²+(√x+√y)²]/(√x+√y)(√x-√y)=(x+y-2√xy+x+y+2√xy)/(x-y)=2(x+y)/(x-y)=2(2+√3)/(2-√3

规范而详细解答过程看图,明白就采纳,祝马年学习进步

√(x-1)-√(1-x)=(x+y)²要使根号有意义x-1≥0且1-x≥0得x≥1且x≤1∴x=1∴0-0=（1+y)²y=-1x=1y=-1代入所求的式子2x分之一减x-y分之

#include#includevoidmain(){intx;inty;while(1){printf("inputx:\n");scanf("%d",&x);if(x=-1&&x

函数y=3+根号x-4

定义域：x≥4.因为根号下的数大于等于0.值域：y≥3.根号开出来的数也是非负的.

原式=-10/3√12x^2*3x/y*x/4y=-10x^2/y=-10/2=-5

1.2^x>04-2^x

简单嘛第一个分数上下同乘以X后面上下乘以Y就有X平方/XY（X+Y)-Y平方/xy(x+Y)（X+Y)(X-Y）/XY(X+Y)X-Y/XY带入就有根号2+1-（根号2-1）除以1等于2拉不太会写数学

函数y=2-4-x²开根号 求值域