2a-b分之a-2ab b 4a-b分之ab-ab计算
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 22:54:35
原式=[4ab/(a-b)+(a²-b²)/ab÷(a+b)/ab]÷(a+b)²=[4ab/(a-b)+(a+b)(a-b)/ab×ab/(a+b)]×1/(a+b)&
=[(2a-b)(a-b)/(a+b)(a-b)-b(a+b)/(a+b)(a-b)]×(a+b)/(a-2b)=(2a²-3ab+b²-ab-b²)/(a+b)(a-b
(a-b分之a-b+3)+(b-a分之b-a+a)-(a-b分之a-b+b+a)=1+(a-b分之3)+1+(b-a分之a)-1-(a-b分之b+a)=1+(a-b分之3)-(a-b分之a)-(a-b
=(a+b)/(a+b)(a-b)-(a-b)/(a+b)(a-b)+2b/(a²+b²)=2b/(a²-b²)+2b/(a²+b²)=2b
原式=[a/(a²-b²)-1/(a+b)]÷[b/(b-a)]=[a/(a²-b²)-(a-b)/(a²-b²)]×[-(a-b)/b]=
原式=(a-b)(a+b)/(a+b)+2a²/(a+b)=[(a-b)(a+b)+2a²]/(a+b)=(a²-b²+2a²)/(a+b)=(3a&
过程在图片上,
解原式=[(a-b)/2(a+b)]-[(a²+b²)/(a-b)(a+b)]=(a-b)²/2(a+b)(a-b)-2(a²+b²)/(a-b)(a
解a-b=(a-b)(a²-b²)/(a²-b²)=(a-b)²(a+b)/(a²-b²)b/(a-b)=b(a+b)/(a
设b=3a=2解得a+b分之a-b=-5分之1
解由(a+b)/b=5/2即2a+2b=5b即2a=3b解得a=3b/2故(a-b)/b=(3b/2-b)/b=(1/2b)/b=1/2
1-(a+2b)/(a+b)=(a+b)/(a+b)-(a+2b)/(a+b)=(a+b-a-2b)/(a+b)=-b/(a+b)再问:��3��10�ĸ����η������Ĵη�������3��
(a-ab)/(a+2b+b-a)/(b-a-b)/2a答:(1)(a-ab)/3b/(-a)/2a(2)/-1/2(3)*-2(4)(a/3b-a/3)*-2(5)-2a/3b+2a/3
=a(a+b)/(a+b)(a-b)+b(a-b)/(a+b)(a-b)-2ab/(a+b)(a-b)=(a²+ab+ab-b²-2ab)/(a+b)(a-b)=(a²-
(a+b)分之2a倍的根号a+
收起(b分之2a)的平方-b分之a除以a分之b=4a²/b²-(a/b)×(a/b)=3a²/b²;您好,很高兴为您解答,skyhunter002为您答疑解惑如
a+b分之2a-b=1(2a-b)/(a+b)=12a-b=a+ba=2b所以(a+b)(2a-b)分之a-b的平方=(a-b)^2/(a+b)(2a-b)=(2b-b)^2/(2b+b)(4b-b)
(a-b)分之1-(a+b)分之1+(a^2+b^2)分之2b=(a+b)/(a²-b²)-(a-b)/(a²-b²)+2b/(a²+b²)
原式=2b/(a²+b²)+(a+b-a+b)/(a²-b²)=2b/(a²+b²)+2b/(a²-b²)=2b[(a&
(a-b)分之1-(a+b)分之1+(a平方-b平方)分之2b=(a平方-b平方)分之2b+(a平方-b平方)分之2b=(a平方-b平方)分之4