2log5^3等于log5^9吗
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/07 08:33:13
第一题:3x
log5(35)+2log0.5(根号2)-log5(0.02)-log5(14)=log[35/(0.02*14)]-1=log125-1=2
数学(log5√2*log79)/(log51/3*log73√4)+log2(√(3+√5)-log√(3-√5))=(lg√2/lg5*lg9/lg7)/(lg1/3/lg5*lg3√4/lg7)
2log5^10+log5^0.25=2lg10/lg5+lg0.25/lg5=lg100/lg5+lg0.25/lg5=(lg100+lg0.25)/lg5=lg25/lg5=2lg5/lg5=2希
log5^41所以log4^5>log5^4log5^3再问:是不是打太快了?log5^41是什么?我想知道详细点的再答:哪里有log5^41首先只有log4^5>1所以log4^5最大无悬念然后1>
10的a次方等于2,10的b次方等于3所以,a=lg2,b=1g3log512=(lg2+lg2+lg3)/(1-lg2)=(2a+b)/(1-a)
log5(35)-2log5(7/3)+log5(7)-log5(1.8)=log5(35*(7/3)^(-2)*7/1.8)=log5(25)=2
log5(4)=log5(2^2)=2log5(2)=blog5(2)=b/2log5(24)=log5(3*4*2)=log5(3)+log5(4)+log5(2)=a+b+b/2=a+3b/2
由lg8000=lg8+lg1000=3lg2+3=3(lg2+1)lg2^√3=√3lg2所以原式=lg5*lg8000+(lg2^√3)^2=3lg5((lg2+1))+(√3lg2)^2=3lg
log4(5)>10
2*log5.10+log5.o.25=log5.10+log5.10+log5.0.25=log5.10*10*0.25=log5.25=5
原式=log5(35)-log5[(7/3)²]+log5(7)-log5(1.8)=log5(35÷49/3×7÷1.8)=log5(5/6)
log5(3)=log3(3)/log3(5)=1/log3(5)换底公式
logab=1/logba,这个是对数的一个性质本题就是:log51/3*log36*log6X=log51/3*(1/log63)*log6X后面两个乘积=log3X所以,原式=log51/3*lo
因为根号下3加2倍根号2等于根号2加1所以1/根号[3加2根号2]等于根号2-1所以log根号2-1底[根号2-1]=1所以log5底1=0完
原式=2*2-3*6=-14
(log3^4+log5^2)(log2^9+log2^根号3)=(lg4/lg3+lg2/lg5)(lg9/lg2+lg根号3/lg2)=(2lg2*lg5+lg2*lg3)/lg3*lg5*(lg
没底?
log3(2)=lg2/lg3log5(3)=lg3/lg5log8(5)=lg5/lg8log3(2)*log5(3)*log8(5)=(lg2*lg3*lg5)/(lg3*lg5*lg8)=lg2
5^log5(2)-4^log2(3)+3^log27(8)=2-2^2log2(3)+27^[(1/3)log27(8)]=2-2^log2(9)+27^[log27(2)]=2-9+2=-5再问: