2x-5y=3,求4∧x÷32y的值-搜答案-百度作业网

|2-x|+|x-y+4|=02-x=0,x-y+4=0x=2,2-y+4=0,y=63（x-y）-5（x-y）^2-3（x-y）+（y-x）^2+4（x+y）^2+3（y-x）=-4（x-y）^2+

x-y=4x5=20①2x+y=5②2x-3y=18③①+②3x=25x=25/3y=-35/3代入③2x-3y=50/3+105/3=155/3≠18题目错误

两个式子作差得到x=5带入得到y=23

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

5x-2y=x-y=4x-3y-2则4x=y代入：x-4x=4x-12x-2得到x=-2/5y=-8/5

可以化简为X到1.2.3...一直到十的距离你画个X轴就出来了可以很明显的得到1和10的中点5.5与1到10的距离和最小所以函数的最小值为25

[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷8x=(9x^2-4y^2-5x^2+2xy-10xy+4y^2)/(8x)=(4x^2-8xy)/(8x)=（x-2y)/2=2012/

楼上的全错,{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²}÷(-4x)={9X²-(5x²-xy-25x²+5y²)-(x&s

x^5+x^4y+x^4+x+y+1=0x^4(x+y+1)+x+y+1=0(x^4+1)(x+y+1)=0然后因为x^4+1不可能等于0所以只有x+y+1=0x+y+1=03x+2y=1这两个公式,

因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6

2y=x-3带入[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/4x=[(3x+x-3)(3X-x+3)-(x+x-3)(5x+3-x)]/4x=(8x2-6x=12x-9-8x2=12

（x+2）^2+|x+y+5|=0,x+2=0,x+y+5=0x=-2,y=-33(x^2)y-2(x^2)y+2xy-(x^2)y+4x^2-xy=4x^2+xy=4*(-2)^2+(-2)*(-3

原式=(9x²-4y²-5x²-8xy+4y²)÷4x=(4x²-8xy)÷4x=x-2y=2011

1不等于-4/32把它改成一元二次就是把分母乘上来然后用Y表示DELTA要其大于等于零可求Y范围32X+7/3或-2X-7

x=1/2(4+5y)原式＝4^1/2(4+5y)÷32^y=2^(4+5y)÷32^y=16*2^5y÷32^y=16

2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6

2x＋y＋3=xy,①若x=1,则y不存在,此时5x＋4y无最值；②若x≠1,则y=(2x＋3)/(x－1),M=5x＋4y=5x＋(8x＋12)/(x－1)=(5x²＋3x＋12)/(x－

1,-3再问：过程。。。再答：★（x²－2x)+（y²－4y）=5★（x－1）²+（y－2）²=1+4－5★（x－l）²=0,（y－2）²=

x+2=0,x+y+5=0x=-2,y=-33x^2y+{-2X^2y-[-2xy+(x^2y-4x^2)]-xy}=3x^2y-2X^2y+2xy-x^2y+4x^2-xy=4x^2+xy=4*4+

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009）y=0+(1×1004-2009)y=-1005y=1005/2