2xy^2 (x^2 y^4)当x,y趋于0的极限

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 22:19:35
2xy^2 (x^2 y^4)当x,y趋于0的极限
当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值

(xy+2y)-(x+2)/x^2-4=【y(x+2)-(x+2)】/(x+2)(x-2)=(y-1)/(x-2)=(7-1)/(3-2)=6

(xy-x^2)乘以(xy)/(x-y)

对.前提是x不等于y

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

计算:4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2

4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2=(4xy-x²-2xy-y²)/[xy(x+y)(x-y)]÷[(x-y)(x+2y

当x=2,y=1时,代数式x^4-xy^3-x^3y-3x^2y+3xy^2+y^4

x^4-xy^3-x^3y-3x^2y+3xy^2+y^4=x^4-x^3y-3xy(x-y)+y^4-xy^3=x^3(x-y)-3xy(x-y)-y^3(x-y)=(x-y)(x^3-3xy-y^

当x-y=1时,求x^4-xy^3-x^3y-3x^2y+3xy^2+y^4的值

x^4-xy^3-x^3y-3x^2y+3xy^2+y^4=(x^4-x^3y)-xy^3+y^4-3x^2y+3xy^2=x^3(x-y)-y^3(x-y)-3xy(x-y)=x^3-y^3-3xy

当x-y=1,求x^4-xy^3-x^3y-3x^2y+3xy^2+y^4的值

x^4-xy^3-x^3y-3x^2y+3xy^2+y^4=(x^4-x^3y)-xy^3+y^4-3x^2y+3xy^2=x^3(x-y)-y^3(x-y)-3xy(x-y)=x^3-y^3-3xy

(x^2+xy/x-y)/(xy/x-y)计算

【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,

当x=-4 y=-2时 求代数式-3x平方y+3xy平方+x?+3x平方y-3xy平方-y,

当x=-4y=-2时求代数式-3x平方y+3xy平方+x?+3x平方y-3xy平方-y,=-3x²y+3xy²+x-y+3xy(x-y)=-3xy(x-y)+(x-y)+3xy(x

(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)

(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=1.=3(a-b)/(10ab)*(25a^2b^3)/((a+b)(a-b))=15/2*(ab^2)/(a+

3x-4y+2xy)--(2x--5y+5xy)=当x+y=5,xy=-3

(3x-4y+2xy)--(2x--5y+5xy)=3x-4y+2xy-2x+5y-5xy=x+y-3xy=5-3*(-3)=5+9=14

当x=2007,y=2008时,求x^4-y^4/x^2-2xy-y^2÷x^2+y^2/y-x=

(x^4-y^4)/(x^2-2xy+y^2)÷(x^2+y^2)/(y-x)=(x^2-y^2)(x^2+y^2)/(x^2-2xy+y^2)*(y-x)/(x^2+y^2)=(x^2-y^2)/(

(xy/(x^2+y^2))^x当x,y都趋于正无穷时极限是多少?

极限不存在.上下同时除以x^2,令t=y/x,则原式=t/(1+t^2).由于t可以是任意非负数,所以极限不存在.

当x=2000,y=-10时计算x^2-2xy+y^2分之x^4-Y^4乘x^2+y^2分之y-x

[(x^4-y^4)/(x^2-2xy+y^2)]*(y-x)/(x^2+y^2)=[(x-y)(x+y)(x^2+y^2)/(x-y)^2]*(y-x)/(x^2+y^2)=[(x^2+y^2)(x

当x/y=3/4时,求分式(xy+y^2)/(x^2-xy)的值

原式分子分母同除以y²原式=[(xy+y²)/y²]/[(x²-xy)/y²]=[(x/y)+1]/[(x/y)²-(x/y)]=(3/4+

当x=2008,y=2009时,求代数式(x-y)/x/(x-(2xy-y^2)/x)

原式=(x-y)/x/((x^2-2xy+y^2)/x)=(x-y)/x乘以(x/(x^2-2xy+y^2))=(x-y)/x乘以(x/(x-y)^2)=1/(x-y)当x=2008,y=2009原式

x^2y+4xy+4y

x^2y+4xy+4y=y(x²+4x+4)=y(x+2)²

已知A除以x²+4xy+4y²分之x²-y²=x+2y分之x+2y,当x=2,y

原式即为A*(x+2y)^2/(x-y)(x+y)=1即A*16/3=1∴A=3/16很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

当x=-1/3时,【十万火急!】化简求值:(9x^2y-6xy^2)÷(-3xy)-【(4y^2-9x^2)/(-3x+

(9x^2y-6xy^2)÷(-3xy)-【(4y^2-9x^2)/(-3x+2y)】=-3x+2y-【(2y-3x)(2y+3x)÷(-3x+2y)】=-3x+2y-2y-3x=-6x=-6×(-1