3x﹣2y除以3＝3x﹢ 2y除以9＝2

原式=（15x²+16xy+4y²+x²-4y²）/4x=(16x²+16xy)/4x=4x+4y此题是利用多项式的乘法及平方差公式进行计算的,希望你

首先你要理解所给集合的元素代表什么.全集U为平面点集,M为两条射线（直线y=x+1除去点（2,3））,N表示平面内除去直线y=x+1以外的点.我想这样你应该能得出结果了吧?有问题继续问我.再问：能再说

原式=(9x²+24xy+16y²-4x²+y²-5x²+6xy-y²)÷(-2y)=(30xy+16y²)÷(-2y)=-15x

分子分母同时除以Y令x比y=Z即使求Z=?(2Z+3)/（5z-3）=3/515Z-9=10Z+15Z=24/5

y=(2x+3)/(x-1)=[2(x-1)+2+3]/(x-1)=2+5/(x-1)x＜1,∴5/(x-1)＜0,∴y＜2或∵x＜1,x-1≠0,变换得y(x-1)=2x+3,即x=(3+y)/(y

解原式=2(x-y)/(x+y)-(x+y)/3(x-y)=6(x-y)(x-y)/[3(x+y)(x-y)]-(x+y)x+y)/[3(x-y)(x+y)]=5(x-y)(x-y)/[(x+y)(x

2x-y/x+3y=2得x+3y/2x-y=1/24x-2y/x+3y减4x+12y除以2x-y=2(2x-y)/x+3y-4(x+3y)/2x-y=2乘以2-4乖以1/2=4-2=2

原式=1/4y[x^2-4*y^2-(x^2+8*xy+16y^2)]=1/4y(-8*xy-20*y^2)=-2x-5y代入得：原式=(-2)*(-2)-5(-3)=19

是{（x+y）2-（x+y）（x+3y）-5y}/2y=【（x+y）（2-x-3y）-5y】/2y=(x+y)(2-x-3y)/5y-2.5带入数字（-2+1/2）(2+2-1.5)/2.5-2.5=

2y=x-3带入[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/4x=[(3x+x-3)(3X-x+3)-(x+x-3)(5x+3-x)]/4x=(8x2-6x=12x-9-8x2=12

原式=[(x-y)(x-y)+(x+y)(x-y)]/2x=(x-y)(x-y+x+y)/2x=(x-y)·2x/2x=x-y=3-1.5=1.5

[(x+2y)²-(x+y)(3x-y)-5y²]÷2x=[x²+4xy+4y²-(3x²+2xy-y²)-5y²]÷2x=[x&

令x除以2=y除以3=z除以4=k则x=2k,y=3k,z=4kx+y+z除以x-2y+3z=(2k+3k+4k)除以(2k-6k+12k)=9k除以8k=8分之9

13y-4x

(x-y)^0/(x-y)^-3*(y-x)^-2=1/(x-y)^-3*(x-y)^-2=1/(x-y)^-1=x-y

[x(x^2y^2-xy)-y(x^2-x^3y)]除以3x^2y=(x³y²-x²y-x²y+x³y²)÷3x²y=(2x

[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/4x=[(9x^2-4y^2)-(5x^2+8xy-4y^2)]/4x=(9x^2-4y^2-5x^2-8xy+4y^2)/4x=(4x^

[3（x+y）³-5(x+y)²-2x-2y]÷(x+y)=3(x+y)²-5(x+y)-2=[(x+y)-2][3(x+y)+1]=(x+y-2)(3x+3y+1)如果

3x除以4等于2y除以5两边乘以4/3左边=x右边=y*2/5*4/3=y*8/15所以x除以y等于8除以15

（-2X^2/Y)^2*(-2Y^2/3X)^2除以(2Y/X)^4=（-2X^2/Y)^2*(-2Y^2/3X)^2/(2Y/X)^4=X^6/(9Y^2)