9x次方=6
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![9x次方=6](/uploads/image/f/418225-49-5.jpg?t=9x%E6%AC%A1%E6%96%B9%3D6)
x的3次方=-8a的6次方b的9次方,x^3=-8a^6b^9x³=(-2)³(a²)³(b³)³=[(-2)(a²)(b&sup
x^5-3x^4+2x^3-3x^2+9x-6=0X^3(x^2-3x+2)-3(x^2-3x+2)=0(x^2-3x+2)(X^3-3)=0(x-1)(x-2)(X^3-3)=0x=1或2或3的根号
t=3^x>0t^2-6t-7=0(t-7)(t+1)=0t=7x=log3(7)
4^x+6^x=9^x(4/6)^x+1=(9/6)^x(2/3)^x+1=(3/2)^x((2/3)^x)^2+(2/3)^x-1=0设(2/3)^x=a则:a^2+a-1=0,a>0a=(√5-1
设3^x=M,2^x=N,则9^x=3^2x=(3^x)^2=M^2,6^x=MN,2^(2x+1)=2N^2,于是原方程化为:M^2+MN-2N^2=0,分解因式得:(M-2N)(M+N)=0,故M
f(x)=12x^6+5x^5+8x^4+11x^3+18x^2+52x+99=x(12x^5+5x^4+8x^3+11x^2+18x+52)+99=x(x(12x^4+5x^3+8x^2+11x+1
4^x+6^x=9^x(4/6)^x+1=(9/6)^x(2/3)^x+1=(3/2)^x((2/3)^x)^2+(2/3)^x-1=0设(2/3)^x=a则:a^2+a-1=0,a>0a=(√5-1
X(X^2-6X-9)-X(X^2-8X-15)+2X(3-X)=X^3-6X^2-9X-X^3+8X^2+15X+6X-2X^2=12x带入X=1/3原式=12*1/3=4
9^x+4^x=5/2*6^x两边同时除以6^x得:(3/2)^x+(2/3)^x=5/2令t=(3/2)^x,则方程化为;t+1/t=5/2t^2-5/2*t+1=0(t-2)(t-1/2)=0t=
∵3^(x)+3^(-x)=2∴等式两边平方,得[3^(x)+3^(-x)]^2=2^29^(x)+9^(-x)+2*3^(x)*3^(-x)=4∴9^(x)+9^(-x)+2=4从而9^(x)+9^
4^x+6^x=9^x方程两边同除以9^x得:(4/9)^x+(2/3)^x=1令t=(2/3)^x则,(4/9)^x=t²原式为;t²+t-1=0由求根公式得;t=(-1±√5)
令3^x=a则9^x=a²a²-6x-7=0(a-7)(a+1)=0a=3^x>0所以3^x=a=7x=log3(7)
题目应该是求a12+a11+a10+...和a12-a11+a10-...的值吧?(1)令x=1则:(x^2-x+1)^6=1=a12+a11+...+a0所以:a12+a11+...+a0=1(2)
答:6^x-9*2^x-3^x+9=0(2^x)*(3^x)-9*2^x-3^x+9=0(2^x-1)*3^x-9*(2^x-1)=0(2^x-1)(3^x-9)=02^x-1=0或者3^x-9=0所
9^2x-y+27^x-y=3^4x-2y+3^3x-3y=3^4x/3^2y+3^3x/3^3y=(3^x)^4/(3^y)^2+(3^x)^3/(3^y)^3=4^4/6^2+4^3/6^3=25
x的立方=-8a的6次方b的9次方x³=-(2a²b³)³x=-2a²b³
(2×3)^x+2^(2x)=3^(2x)2^x×3^x+2^(2x)=3^(2x)令2^x=a,3^x=b则变化为ab+a^2=b^2a^2+ab-b^2=0a1=(-b+√(b^2+4b^2))/
是4^x+6^x=6*9^x吧?两边同除以9^x:(4/9)^x+(6/9)^x=6即(2/3)^2x+(2/3)^2-6=0[(2/3)^x+3][(2/3)^x-2]=0因(2/3)^x>0所以只
x^12+x^9+x^6+x^3+1=(x^12+x^11+x^10+x^9+x^8)-(x^11+x^10+x^9+x^8+x^7)+x^9+x^7+x^6+x^3+1=x^8(x^4+x^3+x^