已知tana=1,sin(2a β)=3sinβ,则tan(a β)=

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已知tana=1,sin(2a β)=3sinβ,则tan(a β)=
已知tanA=1,sin(2A+B)=3sinB,求tan(A+B)?

sin(2A+B)=sin(2A)cosB+cos(2A)sinB,sin(2A)=2tanA/(1+tanA^2)=1,cos(2A)=(1-tanA^2)/(1+tanA^2)=0,则由sin(2

已知tana=1/2,求sin^2a-3sinacosa+4cos^2a解答,

tana=sina/cosa=1/2,所以cosa=2sina,所以根据sin^2a+cos^2a=1,求出sin,cos

已知tana=3 求2sin²a-3sinacosa-1

先不管-1.前面两项除以cos²+sin²,分子分母约掉cos²,代入tan=3.我算得-0.1

已知tana=1/2 求 sin^2a+sina+2的值

sin^2a+sina+2=2sinacosa+sina+2sina/cosa=1/2sin^2a+cos^a=1解出sina和cosa后代入前面的式子就行了.

已知tana/tana-1=-1,求sin²a+sinacosa+2的值?

tana/(tana-1)=-1,tana=1/2sin²a+sinacosa+2=(sin²a+sinacosa)/1+2=(sin²a+sinacosa)/(sin^

已知tan(A-B)/tanA+sin^2C/sin^2A=1,求证:tanA*tanB=tan^2C

tan(A-B)=(tanA-tanB)/(1+tanA*tanB)tan(A-B)/tanA+sin²C/sin²A=1左右移项得1-[(tanA-tanB)/(1+tanA*t

已知sin(a+b)=1/2,sin(a-b)=1/3,求tana/tanb的值

由sin(a+b)=sinacosb+cosasinbsin(a+b)=sinacosb+cosasinb可知sinacosb=[sin(a+b)+sin(a-b)]/2=5/24cosasinb=[

已知tana=根号2,2sin²a-sinacosa+cos²a-1

tana=根号2;sin²a=4/5,cos²a=1/52sin²a-sinacosa+cos²a-1=sin²a-sinacosa=sin²

1.已知sin(a+b)=2/3 ,sin(a-b)=1/5 求 tana/tanb的值

1sin(a+b)=2/3sina*cosb+cosa*sinb=2/3-----------(1)sin(a-b)=1/5sina*cosb-cosa*sinb=1/5-----------(2)联

已知tan(a-r)/tana+sin^2b/sin^2a=1 ,求证tan^2b=tana*tanr..

分析法倒推tanr=-tan(a-r-a)=[tana-tan(a-r)]/[1+tana*tan(a-r)]tana*tanr=[tan^2a-tana*tan(a-r)]/[1+tana*tan(

已知3sinb=sin(2a+b)且tana=1,求tan(a+b).

3*sin(a+b-a)=sin(a+b+a);3*sin(a+b)cos(a)-3*cos(a+b)sin(a)=sin(a+b)cos(a)+cos(a+b)sin(a);2*sin(a+b)co

已知tana=1,3sinB=sin(2a+B),求tan(a+b/2)

tana=1a=kπ+π/43sinB=sin(2a+B)=sin(2kπ+π/2+B)=cosB3sinB=cosBsin^2B+cos^2B=1cos^2B=9/10sin^2B=1/10sinB

已知(2sin^a+sin2a)/(1+tana)=k (0

别做了没用、以后生活也用不着

已知sin平方2a+sin2acos2a-cos2a=1,a在第一象限,求sina,tana

sin平方2a+sin2acos2a-cos2a=1sin平方2a-1+cos2a(2sinacosa-1)=0-(cos2a)^2+cos2a(2sinacosa-1)=0cos2a(2sinaco

已知(1+tana)/(1-tana)=3+2√2,求cos(π-a)方+sin(π+a)cos(π-a)+sin(a-

(1+tana)/(1-tana)=3+2√2化简求得tana=(根号2)/2所以cosa=2/根号6sina=(根号2)/(根号6)cos(π-a)方+sin(π+a)cos(π-a)+sin(a-

已知sin平方2a+sin2acosa-cos2a=1,a属于(0,90),求sina,tana

∵sin²(2a)+sin(2a)cosa-cos(2a)=1∴sin²(2a)+sin(2a)cosa-cos(2a)-1=0==>sin²(2a)+sin(2a)co

已知cosa=1/4,求sin(2π+a)cos(-π+a)/cos(-a)tana

sin(2π+a)cos(-π+a)/cos(-a)tana=sin(a)cos(π-a)/cos(a)(sina/cosa)=-sinacosa/sina=-cosa=-1/4

求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana

sin^2a*tana+cos^2a*1/tana+2sina*cosa=(1-cos^2a)*tana+(1-sin^2a)*1/tana+2sina*cosa=tana-sina*cosa+1/t

已知tana=2,则sin^2a +sinacosa/sin^2+1的值

sin^2a+sinacosa/sin^2+1?是sin^2a+sinacosa/sin^2a+1吧?sin^2a+sinacosa/sin^2a+1=sin^2a+sinacosa/(2sin^2a