已知函数f(x)=cos2x 根号3sin2x a.(a∈R

①原式=f(x)=2cos2x+sinx^2=2cos2x+1-cos2x/2=3/2cos2x+1/2故f(π/3)=3/2*cos2π/3+1/2=-3/4+1/2=-1/4②依f(x)=3/2c

f（x）=sin2x-cos2x+1=√2*(√2/2*sin2x-√2/2*cos2x)+1=√2sin(2x-π/4)+1最小正周期为：T=2π/2=π∵-1≤sin(2x-π/4)≤1∴1-√2

只要cos2x≠0即可,所以定义域为｛x｜x∈R,且x≠k∏+∏/2,k∈Z｝f（x）=1/2（tan2x+1/cos2x+1）tan2x和cos2x在第一象限时的值域为（0,+∞）tan2x和cos

f(x)=(√3)sinxcosx+cos2x+1f(x)=(√3)(2sinxcosx)/2+cos2x+1f(x)=(√3/2)sin2x+cos2x+1f(x)=(√7/2)[(√3/2)(2/

f(x)=2√3sinxcosx-cos2x=√3sin2x-cos2x=2(sin2x*√3/2-cos2x*1/2)=2sin(2x-π/6)x=π/12;函数f(x)的图象可以由函数y(x)=2

分式有意义,cosx≠0f(x)=[sin(2x)+cos(2x)+1]/(2cosx)=(2sinxcosx+cos²x-sin²x+cos²x+sin²x)

首先：定义域只有这一个,X+π/4≠2Kπ,所以X≠-π/4+2kπ..附上值域,化简原函数：f（X）=cos2X/[√2/2（sinX+cosX）]f(x)=(cos²X-sin²

(1)f(x)=a*b=(√3sin2x,cos2x)(cos2x,-cos2x)=√3sin2x*cos2x-cos2x*cos2x=(√3/2)sin4x-(cos4x+1)/2=(√3/2)si

字数限制f(x)=cos2x+(1-cos2x)/2+sin2x/2=(cos2x+sin2x)/2+1/2=cos(2x+π/4)/根号2+1/2其最小正周期为π,最大值为：(1+根号2）/2x在[

一f(x)=sin"x+cos"x+2sinxcosx+cos2x=1+sin2x+cos2x=_/2sin(2x+派/4)+1所以T=2派/2=派"指平方“_/2”指根号2二因为X属于[0派/2]是

已知函数f(x)=根号3sin2x+cos2x+21求f(x)的最大值及f(x)取得最大值时自变量x集合f(x)=根号3sin2x+cos2x+2=2[(根号3/2)sin2x+(1/2)cos2x]

cos2x=sin(π/2-2x)=2sin(π/4-x)cos(π/4-x)cos2x/[sin(π/4-x)]=2sin(π/4-x)cos(π/4-x)/[sin(π/4-x)]=2cos(π/

（1）f（x）=3sin2x+cos2x=2（sin2xcosπ6+cos2xsinπ6）=2sin（2x+π6）∴T=2π2=π，当2x+π6=2kπ+π2，k∈Z，即x=π6+kπ，k∈Z时，函数

f(x)=√2sin（2x+π/4)-1（1）最小正周期π；最大值√2（2）2kπ-π/2≤2x+π/4≤2kπ+π/22kπ-3π/4≤2x≤2kπ+π/42kπ-3π/8≤x≤2kπ+π/8

f(x)=2cos2x+sinx=2-4*(sinX)^2+(sinX)^2=2-3*(sinX)^2f(π/3)=-3*（9/4）+2=-1/4f(x)的最大值2最小值-1

f(x)=sin2x+cos2x=√2sin(2x+π/4)f(π/4)=√2sin(2*π/4+π/4)=√2*√2/2=10

f(x)=sin2x+cos2x=√2sin(2x+π/4)所以T=2π/2=π最大值=√2f(θ+π/8)=√2sin(2θ+π/4+π/4)=√2cos2θ=√2/3cos2θ=1/3θ锐角则si

f(x)=√3sinxcosx+cos2x+1=(√3/2)sin2x+cos2x+1=[(√7)/2][(√3/√7)sin2x+(2/√7)cos2x]+1=[(√7)/2]sin(2x+α)+1

f(x)=2(1－2sin²x)＋sin²x=2－3sin²x1、f(π/3)=2－3/4=5/4；2、f(x)的最大值是2,最小值是-1

f(x)=1-2x^2