百度作业网已知函数fx等于根号3sin
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 10:51:26
派,负四分之派到四分之派,再问：可我不知道怎么写过程。
y=f(x)的图像过点(2,根号2)根号2=2^nn=1/2y=x^1/2f(9)=3
f(x)=[(cosx)^2-(sinx)^2]+√3sin2x=cos2x+√3sin2x=2sin(2x+π/6),最小正周期T=π,由-π/2+2kπ≤2x+π/6≤π/2+2kπ,k∈Z解得：
f(x)=-√3sin²x+sinxcosx＝√3/2cos2x+1/2sin2x-1/2=sin(2x+π/3)+1/2T=2π/2=πf(π/6)=sin(π/3+π/3)+1/2=(1
f(x)=√3sin²x+sinxcosx=√3[(1-cos2x)/2]+1/2sin2x=1/2sin2x-√3/2cos2x+√3/2=sin(2x-π/3)+√3/2∵x∈[π/2,
当f(x)=2时,则√3sin(2x+π/4)+1=2.√3sin(2x+π/4)=1.sin(2x+π/4)=√3/3.2x+π/4=2kπ+arcsin(√3/3).2x=2kπ+arcsin(√
f(x)=1/2-1/2cos2x+√3/2sin2x-1/2=sin(2x-π/6)f(-π/12)=sin(-π/3)=-√3/2(2)-π/6
f(x)=2√3sinxcosx+2sin^2x-1=√3sin2x-cos2x=2sin(2x-π/6)最小正周期T=π,单调递增区间:2kπ-π/2
因为f（x）是偶函数,所以f（x）=f（-x）,比较对应项得：sinx（根号3sina+cosa）=0所以根号3sina+cosa=0,得：2sin(a+π/6)=0,即：a+π/6=kπ+π/2,所
答：f(x)=2sin(x-π/3)cosx+sinxcosx+√3(sinx)^2=sin(x-π/3+x)+sin(x-π/3-x)+sinxcosx+(√3/2)(1-cos2x)=sin(2x
答：y=f(x)=2√3sinxcosx-2sin²x=√3sin2x+cos2x-1=2*[(√3/2)sin2x+(1/2)cos2x]-1=2sin(2x+π/6)-1y=f(x)关于
f(x)=√(4x-1)+√(3-4x)定义域A：4x-1>=0且3-4x>=0x>=1/4且x
第一题A.第二题B
（1）化简可得f(x)=(sin(x/2))^2+((√3)/2)sinx-0.5f'(x)=sin(x/2)cos(x/2)+((√3)/2)cosx=sinx+√3cosx=0√3cosx=-si
解答；f(x)=sin(2x+3分之π)∴sin(2x+π/3)=-3/5∵x∈(0,π/2)∴2x+π/3∈(π/3,4π/3)∵sin(2x+π/3)
解1当2kπ-π/2≤2x+π/3≤2kπ+π/2,k属于Z时,y是增函数即2kπ-5π/6≤2x≤2kπ+π/6,k属于Z时,y是增函数即kπ-5π/12≤x≤kπ+π/12,k属于Z时,y是增函数
f(x)=sin(x/2)cos(x/2)+√3*sin²(x/2)+√3/2=1/2*sinx+√3/2*(1-cosx)+√3/2=1/2*sinx-√3/2*cosx+√3=sin(x
fx=2根号3sinxcosx+1-2sin^2x=2sin（2x+π/6）周期为π
f(x)=√3sin2x-2sin²x=√3sin2x-(1-cos2x)=2sin(2x+π/6)-1∴当sin(2x+π/6)=1时f(x)max=2*1-1=1