c 编写分数前面几项之和
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![c 编写分数前面几项之和](/uploads/image/f/491661-45-1.jpg?t=c+%E7%BC%96%E5%86%99%E5%88%86%E6%95%B0%E5%89%8D%E9%9D%A2%E5%87%A0%E9%A1%B9%E4%B9%8B%E5%92%8C)
#includeintmain(){inta[40],sum=2,i;a[0]=1;a[1]=1;for(i=2;i
intmain(void){inti,ans;For(i=1;i再答:�������ټ�һ��#include再问:лл
#include#include#includeintmain(void){longn,x,jc=1,t;doublesum=1;scanf("%d%d",&n,&x);for(inti=1;i再问:
#include#includeintmain(void){intn;doublei,j,k;doubleres=0;printf("pleaseinputn:");scanf("%d",&n);i=
帮你写好了.unsigned int fib(unsigned int n) {\x09if (n == 1
#include "stdio.h"void main(){ int n,sum=0; printf(&q
#includeintmain(){intx;inta[20];scanf("%d",&x);inti;for(i=0;x>=10;i++){a[i]=x%10;x=x/10;}
你写的scanf就提出了要求的输入是“数a”“逗号”“数b”,你既然没有给出逗号,那就一直没有给b赋值,你也没有给b一个初始化的值,那么得出的结果就是一个随机数.可以把逗号去掉,这样两个数字之间用个空
/*1-2/3+3/5-4/7+5/9-6/11+.的前n项之和*/intmain(intargc,char*argv[]){intnum_n=1;inti=0;doubleresult=0.0;pr
#includeintmain(){inta=2;intc=3;intsum=2;inti;for(i=1;i
#includevoidmain(){inti=0,j=0,k=0;for(i=1;i
#includeintmain(){inta,b,c,min,max;printf("请输入三个数,用空格键隔开");scanf("%d%d%d",&a,&b,&c);min=ac?b:c);prin
#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i
main(){inti,n,sum=0;scanf("%d",&n);n*=2;for(i=1;i
main(){intsum,i,j,n;ints[n][n];for(i=0;i
不用那么麻烦inta=1,b=2,i,k,n;floatsum=0.0;scanf("%d",&n);for(i=0;i再问:不是题目要用递归函数
#includemain(){inti,j,n,k,t;doublesum=2;printf("inputanumber:\n");scanf("%d",&n);j=2;k=1;for(i=1;i再问
10个数正数和:#include<stdio.h> #define N 10 void main() {
#include <stdio.h>long u, v;void addrat(int, int);void lowterm()
#includedoublefun1(intn){inti;doublesum=0;for(i=1;i