c语言用递归函数编程输出菱形

#includefun(intx,intn){if(n==0)return(1);elsereturn(x*fun(x,n-1));}main(){intx,n;scanf("%d,%d",&x,&n

#include <stdio.h>int diffabs(int a,int b) { // 返回a,b差值的绝对值

#include <stdio.h>/* 能输出n个空格的函数 */void repspace(int n) { &n

#include#defineN4main(){inti,j,a[N][N]={{3,5,6,3},{0,8,9,1},{0,0,5,0},{0,0,0,7}};for(i=0;ifor(j=0;ji

#includevoiddraw()//子函数{inti,j,k;for(i=1;i再问：我想在主函数里面输出再答：你好intmain()//主函数{draw();return0;}主函数里的draw

#include#defineCOL5//一行输出5个longfibonacci(intn){//fibonacci函数的递归函数if(0==n||1==n){//fibonacci函数递归的出口re

#include<stdio.h>int main(){int i,j;for(i=0;i<6;i++){for(j=1;j<6-i;j++)

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

voidprt(intn){printf("%d",n%10);if(n>10)prt(n/10);}intmain(void){inta;printf("请输入整数：");scanf("%d"

#include <stdio.h>char* dg(char* instr, char* outstr, char* 

intFibona(intn){intm;if(n==1)return(1);elseif(n==2)return(1);else{m=Fibona(n-1)+Fibona(n-2);return(m

#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\

#include#include#includeintmain(void){srand(time(0));inti=0;//用于下面的循环inta[20]={0};//用于存储产生的20个随机数.do

直角三角形#include#defineN10intmain(){inti,j;for(i=1;i再问：if(j

#include#includeintmain(intargc,char*argv[]){intm,n,c,i,j,max;scanf("%d%d",&m,&n);if(m=2){printf("Th

for(i=-3;i再问：谢谢啦，但是能不能不调用函数解决啊~~

#defineN5#include<stdio.h>voidmain(){  inta[N][N];  inti,j;  for

voidmain()intx,abs;printf("shurux");scanf("%d",&x);if(x>0)abs=x;elseabs=0-x;printf("jueduizhishi%d",

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){chari,ci,j,n,ch;printf("请输入菱形中心数.