C语言输入n,输出1-2 3-4...n的结果-搜答案-百度作业网

doublefun(intn)

sum=flag*item+sum;item=1/temp;这两句换一下位置.还有fun函数返回值改为double

一次循环就解决的,不是很难,为什么不自己尝试一下呢?给你提示一下,却是不会再给你说吧!真正想学习,最好多练习一下好不好?累乘初始值为1,循环变量循环n次,每次累乘m,循环结束即为m的n次方的值

#include#defineNUM6//n=6则写6,n=15则写15voidmain(){inti,j,k;for(i=0;i0;j--)//控制空格{printf("");}for(k=0;k

你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs

if(flag==1&&n!=1)这里错了你少了=

#includevoidmain(){inti,n,sum=0;printf("请输入n:\n");scanf("%d",&n);for(i=1;i

#includeintmain(){intn,i,t;floats,a;scanf("%d",&n);a=0;s=0;for(t=n;t>=1;t--){a=0;for(i=1;

#include<stdio.h>int main(){ int n; do

#includeintmain(){inti,n,sum;printf("请输入整数n:\n");scanf("%d",&n);for(i=1,sum=n;i{printf("%d的%d次方等于%d\

#include <stdio.h>void main (){ int a[10]; int i,k=0,n,min,

#include"stdio.h"#include"stdlib.h"intf(intn){while(n>=9){if(n%10==9){return0;}else{n=n/10;}}return1

#include#includevoidmain(){intn;printf("pleaseinputn:");scanf("%d",&n);inti,j,sum;for(i=1;i

#include<stdio.h>int main(){ int n,i,j,k=1;

输入4,输出1234123412341234（样例）#includevoidmain(){intn;inti,j;scanf("%d",&n);for(i=1;i

#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N：\n");scanf("%d",&N);printf("请输入N个整数：\n

#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i

方法很多,以下是按照各边的次序填充再输出：#include<stdio.h>intmain(){inti,j,a[100][100],n,k=1;printf("pleaseinputan

IconfessthatI'mansweringfortask.#includeintmain(){intn,m=1,i=1;scanf("%d",&n);if(n{printf("error\n")

inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=