求y=x,y=2x和y=x^2所围平面图形的面积-搜答案-百度作业网

2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]

你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=（x平方-y平方）/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

原式=(2x-y)(x+y)/(2x-y)^2=(x+y)/(2x-y)x/y=2x=2y原式=3y/3y=1

这道题实际就是要把x^2+y^2变换成只由x+y和y组成的多项式x^2+y^2=x^2-y^2+2y^2=(x+y)(x-y)+2y^2=(x+y)[(x+y)-2y]+2y^2将式中(x+y)替换为

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

x(x+y)(x-y)-x(x+y)2=x(x+y)[(x-y）－（x+y）]=x（x＋y）（－2y）=－2xy（x＋y）=－2×（－1/2）×1=1再问：18p3q3-2pq再答：7(x-1)3-1

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

应该是4x+2y=304x+y=22吧再问：��x��y�ֱ��Ƕ��١�再答：4x+2y=224x+y=30�ó�y=22-30=-8��y=-8��뵽4x+2y=22�еó�4x+��-16��

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

即y/x=2arctan(y/x)令u=y/x,则u=2arctanu这实际是一个关于u的方程,可以证明这个方程是有解的,设u=c是方程的解(这时c已经是一个常数了)即u=y/x=c那么有y=cx所以

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

y=ln(x^2+e^x) 求Y'X

如果是求导数的话,y'=(2x+e^x)/(x^2+e^x)

x+y/y=11/8说明11y=8（x+y）即8x=3y所以x-y/x+2y=3（x-y）/3(x+2y)=（3x-3y）/(3x+6y)=(3x-8x)/(3x+16x)=-5/19

原式化简=x＋2y=2011

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009）y=0+(1×1004-2009)y=-1005y=1005/2