java 给出一个包含n个整数的数列,问整数a在数列中的第一次出现是第几个.

publicvoidchageNum(intm,intn)int[]arr=newint[m];intnewarr=newint[m+n];for(inti=0;i

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

代码如下#includeintasd(inta){inti,t=0;for(i=2;i

publicinterfaceshape{publicdoublearea();}publicclassrectangleimplementsshape{}publicclasscircleimple

分解质因数,日过它只有1和本身,就说明是质数～

if(a==x[i])//多了个分号

只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

楼上两位全错了……不解释,不信自己手算.定理：求前n个奇数的总和=n的平方varn:longint;beginreadln(n);writeln(n*n);end.

#includeintmain(intargc,constchar*argv[]){inta;intb=0;inti=1;printf("请输入数字：");scanf("%d",&a);for(int

给你个例子看看吧privatestaticintmove=3;publicstaticvoidmain(String[]args){int[]arr={1,2,3,4,5,6,7,8,9};Integ

intcount=0;for(intm=1;.){if(m%2==1||m==1){count++;}elseif(m是十位、百位、千位...的情况,其实也是分别除10、100、1000...,再取整

publicclassTest{publicstaticvoidmain(String[]args){inta=Integer.parseInt(args[0]);intn=Integer.parse

varn,i,ans:integer;beginreadln(n);ans:=0;//读入,计数器置0fori:=1tondoifnmodi=0theninc(ans);//从1到n循环找到一个他的因

importjava.util.Scanner;publicclassjiechen{publicstaticvoidmain(String[]args){Scannerscanner=newScan

vari,n,r:longint;s:single;beginreadln(n);fori:=1tondobeginreadln(r);writeln(r*r*3.1415926:0:2);end;e

importjava.io.File;importjava.io.FileNotFoundException;importjava.io.FileWriter;importjava.io.IOExce

对数组进行排序,然后将相邻的如果相等的去掉就可以了intm=0;for(i=1;i

vari,n:longint;beginreadln(n);i:=7;whilei

varn,i,j,s:integer;x:boolean;beginread(n);s:=2;x:=true;ifn