java从键盘输入一个整数,计算有多少位,各位之和,反数(位置反转).

10以内的数判断是否为素数,可以不用任何算法建个数组将0~9以内的素数放在里面,{1,3,5,7}将输入的数字与数组内的数比较,如果有相同就是素数,没有相同的,就非素数.

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

import java.util.Scanner;  public class TestJT {  public&nbs

#includeintfun(intn){inti,j;for(i=2;i

已修改好：#include"iostream.h"int main(){ int i; cin>>i; if(i%3=

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

#include#includevoidmain(){intn,s,j,i;printf("inputn(n

importjava.util.*;publicclassCombination{publicstaticvoidmain(String[]args){VectortestData=newVector

oolcalc(unsignedintn){if(n

packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{

BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为

看看谁的效率高过我importjava.util.Arrays;importjava.util.InputMismatchException;importjava.util.Scanner;publi

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

我觉得这才是楼主的意思吧,首先判断能否同时被5和6整除,如果不能再单独判断是否能被5或者6整除.importjava.util.Scanner;publicclassTest{publicstatic

importjava.applet.*;importjava.awt.*;importjava.awt.event.*;publicclassTest3_2extendsAppletimplement

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S