编写函数,判断一个年份是否为闰年,在主函数
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/31 11:20:06
inputaif(amod4)=0and(amod100)>0thenprint"是闰年"elseif(amod400)=0thenprint"是润年"elseprint"不是闰年"endifendi
inputaif((amod4)=0and(amod100)>0)or(amod400)=0thenprint"是闰年"elseprint"不是闰年"再问:mod是什么再答:mod是求余数,即4mod
可能是太简单了,难得有人回读了,网上一大堆.我手写,没调试:dimy%onerrorgotoline1y=inputbox("输入年份:")'input-inputboxif((ymod4)=0and
inputaif((amod4)=0and(amod100)>0)or(amod400)=0thenprint"是闰年"elseprint"不是闰年"你反着用应该行吧.
if(year%400==0||(year%4==0&&year%100!=0))...
inputn;if(nmod4=0)and(nmod100)0thenprint('yes')elseifnmod400=0thenprint('yes')elsewriteln('no');endi
#includemain(){intt;intis(intt);printf("输入年份为");scanf("%d\n",&t);t=is(t);if(t=1)printf("%d是闰年",t);el
//c++#includeusingnamespacestd;intmain(){intyear;cin>>year;if((year%400==0)||((year%4==0)&&(year%
intjudge_leap_year(){intyear;intok=0;printf("Pleaseinputtheyear:");scanf("%d",&year);if(yea
inputaif((amod4)=0and(amod100)>0)or(amod400)=0thenprint"是闰年"elseprint"不是闰年"你反着用应该行吧.这样可以么?
#include"stdio.h"intisprime(inta){intj;for(j=2;j
#includevoidmain(){intyear;//定义变量printf("请输入一个年份");//提示用户输入scanf("%d",&year);//接收用户输入if((year%4==0&&
#includemain(){intt;intis(intt);printf("输入年份为");scanf("%d\n",&t);t=is(t);if(t=1)printf("%d是闰年",t);el
#include<stdio.h>int isPrime(int num);int main(){ int num; print
//也不说用什么语言,我用C语言来实现!#include#includeintprime(intm){inti,n;if(m==1)return0;n=(int)sqrt((double)m);for
intyearprintf("请输入一个年份");scanf("%d",&year);if((year%4==0&&year%100!=0)||year%400==0)print("闰年\n");el
'判断一个数m是否是完数,是则返回True,否则返回FalseFunctionTestWanShu(ByValmasLong)AsBooleanDimSumAsLongDimiAsLongIfm
FunctionisRun(lYearAsLong)AsBooleanIflYearMod400=0ThenisRun=TrueElseIf((lYearMod4=0)And(lYearMod1000
“在列表框显示1000以内的完数”为什么要放在主调程序里呢?在IsWs函数中已经把完数的因子算出来了,却只能返回一个true,岂不在主调程序里还要算一遍因子才能显示成6=1+2+3这种形式.你又没说要
#include"stdio.h"#include"conio.h"intfun(intn){intflag=0;if(n%4==0){if(n%100!=0)flag=1;}if(n%400==0)