编写程序,实现:求出1到100之内能被7或者11-搜答案-百度作业网

#include<stdio.h>intmain(){ printf("%d",count(100)); &nb

intmain（void）｛inti,ans;For(i=1;i再答：��ټ�һ��#include再问：лл

////////////////////下面是whileintsum=0;int_i=0;while(_i

#includevoidmain(){intsum=0;for(inti=1;i

PublicSubqqqqq()DimiAsIntegerDimjAsIntegerDimsAsIntegerDimCAsBooleans=0Fori=2To100C=FalseForj=2Toi-1

fori=100to500ifimod5=4andimod7=2thensum=sum+1nextprintsum再问：这是完整的吗我是新手不好意思麻烦一个完整的要直接刻通过的再答：将它放入按钮事件即

dimiaslongdimsumaslongsum=0fori=1to100step2sum=sum+inextiprintsum

#include <iostream>#include <string>#define M 4#define N 4

intsum=0;for(inti=100;i

#includeusingnamespacestd;classSUM{private:intC_array[5][5];ints;inta;intb,m,n;public:SUM(){}SUM(int

#includevoidmain(){ints=0;for(inti=0;i

intsum=0;for(inti=0;i{if(i%3!=0){sum+=i;}}

用C++语言么?那应该很简单for(inti=1;icout

#includeusingnamespacestd;intmain(intargc,char*argv[]){inti,sum=0;for(i=1;i

#include <stdio.h>int main() {int i = 1000;doif (555555

#includeintmain(intargc,char*argv[]){inti,j,a[4][4],sum=0,p=1,max,maxi;for(i=0;i再问：请问intargc,char*ar

cleari=0dowhilei

直接用用函数polyfit就可以实现多项式拟合了,p=polyfit(x,y,n),其中x,y为需要拟合的数据向量,n为多项式的次数,p为降幂排列的多项式系数向量.

PrivateSubCommand1_Click()s=0zf=0Fori=1To10s=InputBox("第"&i&"位评委给分:")zf=zf+sNextiPrint"总得分："&zfEndSu

#include#includevoidmain(){inti,j,sum=0,s;for(i=3;i{s=sqrt((double)i);for(j=2;j{if(i%j==0)break;}if(