编程实现程序:输入身高,体重求BMI

for(inti=0;i

楼上两位的代码可能有点小问题s += m*m+1/m;改成s += m*m+1.0/m;再问：您好，请您帮忙写一个完整的编程好么？谢谢了再答：#include&

publicclassa{publicstaticvoidmain(Strings[]){intsum=0,count=0;for(inti=100;i0)continue;sum+=i;count+

#include <iostream>#include <string>#include <stdlib.h>using n

T0101G97S1000M03G0X50.0Z3.0G73U4.0W0.5R4G73P10Q20U0.5W0.05F0.2N10G0X34.641Z1.0G1Z0.0G3X36.81Z-17.826

intfun(intn){returnn%2;}intmain(){intn;printf("\n输入要判断的整数");scanf("%d",&n);if(fun(n)==0)printf("\n%d

#include#includevoidmain(){inta[5][5],s,n=5,i,j;scanf("%d",&s);for(i=0;i

#includeintmain(){floatheight,weight,bmi;shortflag=-1;char*extent[]={"偏瘦","正常","超重","轻度肥胖","中度肥胖","重

#includevoidmain(){intn,i,flag=1;/*变量n存需累加的项数,flag存每项的符号.*/doublesum,item;/*变量sum存累加和,item存每项的值.*/__

#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s

x=1200:400:4000;y=1200:400:3600;[xx,yy]=meshgrid(x,y);zz=[1130,1250,1280,1230,1040,900,500,700;1320,

1,#includelongfoo(intn){if(1==n)return1;returnn*f(n-1);}intmain(void){intm,n,k;scanf("%d%d%d",&m,&n,

#include"stdio.h"intsum(inta[]){\x09inti,result=0;\x09for(i=0;i\x09\x09result+=a[i];\x09returnresult

#include#defineSURPLUS(a,b)(a%b)main(){inta,b;printf("pleaseinputinteger:");scanf("%d,%d",&a,&b);pri

#include <stdio.h>void main(){\x05int i, j, array[5][5], sum=0;\

12岁的身高和体重可以下列公式粗略计算：（注：年龄是指实周岁）体重（kg）=年龄×2＋7（或8）身高（cm）=年龄×5＋75有上述公式计算的体重仅是大约平均数,由于小儿体型、所在地区、种族、生活习惯等

main里面的aver应该写成0.0,然后就是f2里面的i应该赋值为i=0

#include <iostream>void main(){    int a,b,sum,n=0; &n

话说贴吧的大神还是很多的.

module(opcode,a,b,c);reginput[1:0]opcode;regoutputc;always@(opcode)begincase(opcode)2'b00:c=a/b;2'b0