编程统计10个整数中正数的个数

#includemain(){intt,i,c0=0,c1=0,c2=0;for(i=0;i

#includeusingnamespacestd;intmain(){inta[20];intsum=0,count1=0,count2=0;inti;for(i=0;i>a[i];if(a[i]=

packagetest;importjava.util.Random;publicclassrandomNum{publicstaticvoidmain(String[]args){chec

PrivateSubCommand1_Click()Dima(50),i,nRandomizeFori=1To50a(i)=Int(Rnd*191)+10Printa(i);IfiMod10=0The

把if(n=0)改为(n==0),我帮你用数组改了下#includevoidmain(){inti,a=0,b=0,c=0,array[20];printf("pleaseinput20numbers

DATASEGMENTBUFDW12,0,-13,45,-23,0,-34,-12,34ZHENGDB0FUDB0COUNTEQU(ZHENG-BUF)/2DATAENDSCODESEGMENTASS

#include "stdio.h"int main(){   int count1=0,count2=0,i;&nbs

统计DA_WORD数据区中正数、0、负数的个数,数据定义如下：DA_WORDDW-1,3,5,0,-5,-7,4,0,-8……COUNTEQU$-DA_WORDNUMDB0；存放正数的个数DB0；存放

#include#includemain(){inti,j,m,n,a[1000];scanf("%d",&i);//数的个数for(j=0;j

#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i

#includevoidmain(){\x09inta[20],sum=0,count=0;\x09printf("请输入20个整数\n");\x09for(inti=0;i0)\x09\x09{\x

intqugewei(intn)returnn%10;//该函数接受一个数,返回这个数的个位intqushiwei(intn)return(int)n/10;//该函数接受一个数,返回这个数的十位应该

#include#defineN10intmain(){inti,zh,fu,ling;inta[N];int*pa;pa=a;for(i=0;i

dimiasinteger,nasinteger,sasinteger,kasintegerfori=1to10k=val(inputbox("请输入一个整数："))ifkmod2=1thenn=n+

#includemain(){inti,n=0,sum=0;inta[10];printf("n\输入10个数:");for(i=0;i

intmain(){inttemp;/*用于临时保存输入的整数*/intsum=0;/*用于求和*/intcount=0;inti;/*输入这10个数*/for(i=0;i{scanf("%d",&t

#includeintmain(){inta[10]={1,-1,2,0,5,-6,7,0,-2,0};inti,num_po=0,num_in=0,num_ze=0;for(i=0;i0)num_p

publicstaticvoidtest(){Scannersc=newScanner(System.in);longnum=0,negative=0,positive=0,sum=0;Listnum

#includevoidmain(){inta[20];inti;inti1=0;inti2=0;intsum=0;floataver;for(i=0;i

#include#include#defineMAX1000intmain(){inta[MAX],i,j,n,p,q,s1,s2;p=0;q=0;s1=0;s2=0;printf("请输入要输入的值