编程计算1~100所有偶数之和
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#includevoidmain(){intn;ints=0;printf("请输入一个正整数:");scanf("%d",&n);printf("该整数除1和其本身的因子为:\n");for(int
#includemain(){inti,sum=0;for(i=0;i
现在命令窗口输入:modifycommandqh让后在弹出了窗口中输入:clearstore0tosfori=8to100ifmod(i,8)=0s=s+iendifendfor"10到100之间的所
C语言的.#include"stdio.h"main(){floatn=0;floatsum=0;for(;n
1、clears=0fori=1to100ifi%3=0s=s+iendifendfor"1~100之间所有3的倍数之和:",s2、值太大,计算不出结果3、clears=0fori=1to100s=s
#include"stdio.h"voidmain(){intsum1=0,sum2=0,i;for(i=1;i
#includeintmain(void){inti,sum;sum=0;for(i=1;i
只会做第1个:PrivateSubCommand2_Click()Dimi%Fori=100To500x=i\100y=i\10Mod10z=iMod10Ifx+y+z=5ThenPrintiNext
#includevoidmain(){intsum=0,i;intoushu=0,jishu=0;for(i=0;i
assumecs:code;将CS段寄存器与code段关联codesegment;code段start:movbl,10;这里用AL来传送多少以内的数字callsub1;调用子程序mov
clears=0fori=2to100step2s=s+iendfo
2+4+6+..+100=(2+100)*50/2=2550
vara,b,c,d,e,f,g,i,x,y:longint;begine:=1;fori:=6to100doifimod2=0thenforb:=3toidiv2dobegine:=1;forc:=
PrivateSubCommand1_Click()Dimoushu%,danshu%,sum%oushu=0danshu=0Fori=1To10Randomizesum=Int(Rnd*100)If
publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i
1.若包含100、200共101个数,则100+(200-100)/2=200-(200-100)/2=150答案填150!2.1/[(1/72+1/63+1/56)/2]=42答案填42!3.(2*
declarev_countnumber:=1;v_sumnumber:=0;beginforv_countin1..100loopifmod(v_count,2)=0thenv_sum:=v_sum
Functionsu(x:longint);boolean;vari:longint;beginifx
clearallclca=1:100;sum=0;fori=1:100ifrem(a(i),2)==0sum=sum+a(i);elsecontinueendend