编程输入一个整数m(int型),输出该整数的位数n

一：#includevoidmain(){inta,i=0,sum=0;scanf("%d",&a);while(a){sum+=(a%10);//sum是个位数之和a/=10;i++;//i为位数}

你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

/>#include <stdio.h>int main(){\x09int n, cnt = 11;\x09scanf(&qu

我这个效率最高,最直观#include<math.h>#include<stdio.h>voidmain(){_开始:printf("请输入待分析的正整数\n");intn待分

将浮点数先转换为整形数,得到整数部分,再将该实数乘以几百倍,该数减去整数部分得到小数.

if(a%2==0);有个分号

什么语言?再问：c++再答：#includeusingnamespacestd;intmain(){intn,i,j,max=0;cin>>n;for(i=0;i>j;if(j200)break;if

PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If

#includeintmain(){intn,sum=0;printf("请输入一个整数：");scanf("%d",&n);while(n){sum=sum+n%10;n/=10;}printf("

#includeintgcd(intm,intn){\x09intr;\x09do\x09{\x09\x09r=m%n;\x09\x09m=n;\x09\x09n=r;\x09}while(r!=0)

#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin

inti,j,a[20],t,number,k;\x09\x09for(i=0;i

写成函数,直接调用Functionprint_num(ByValnumAsInteger)Dimi,n,k,jAsIntegerDimstrAsStringn=Int(num/2)k=0IfnumMo

IconfessthatI'mansweringfortask.#includeintmain(){intn,m=1,i=1;scanf("%d",&n);if(n{printf("error\n")

#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing

intnumber;scanf("%d",&number);if(number%3==0&&number%5==0){printf("YES");}else{printf("NO");}

#includevoidmain(){intn,sum=0,digit=0;scanf("%d",&n);while(n!=0){sum+=n%10;digit++;n/=10;}printf("每位

#include#includeboolisPrime(intn){if(n==1)returnfalse;for(inti=2;i*i

修改好了#include "stdio.h"#include "math.h"int prime(int n){&nbs