编程输入一个整数nn大于0,小于10
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#includevoidmain(){inti,n,z,f,x;printf("请输入一共要处理几个数:");scanf("%d",&n);for(i=z=f=0;i0)z++;elseif(x
意思是:输入一个数,比如是5,那么求计算1+...一直加到5的和.就这么一个小程序我把程序代码也贴出来给你吧:import java.util.Scanner;public cla
#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);
/>#include <stdio.h>int main(){\x09int n, cnt = 11;\x09scanf(&qu
将浮点数先转换为整形数,得到整数部分,再将该实数乘以几百倍,该数减去整数部分得到小数.
#include/**希望你自己能够看得懂..利用了递归的思想*//**@author:banxi1988*@date:2010-12-12**/intcanuse(intx,intk){if(x
什么语言?再问:c++再答:#includeusingnamespacestd;intmain(){intn,i,j,max=0;cin>>n;for(i=0;i>j;if(j200)break;if
PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If
#includeintmain(){intn,sum=0;printf("请输入一个整数:");scanf("%d",&n);while(n){sum=sum+n%10;n/=10;}printf("
#includeintchange(int);voidmain(){intc,d;cout
INPUT"请输入一个大于2的整数"TONFLAG=T//这个t是表示ture,flag是一个标记变量,FORI=2TON-1//这个循环i的值由2-i-1IFMOD(N,I)=0//在2-i-1这些
#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin
defsquare_up(n):L=[]foriin[[0]*(n-i)+list(range(i,0,-1))foriinrange(1,n+1)]:L+=ireturnL其中列表表达式生成的是形如
inti,j,a[20],t,number,k;\x09\x09for(i=0;i
写成函数,直接调用Functionprint_num(ByValnumAsInteger)Dimi,n,k,jAsIntegerDimstrAsStringn=Int(num/2)k=0IfnumMo
IconfessthatI'mansweringfortask.#includeintmain(){intn,m=1,i=1;scanf("%d",&n);if(n{printf("error\n")
#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing
intnumber;scanf("%d",&number);if(number%3==0&&number%5==0){printf("YES");}else{printf("NO");}
#includevoidmain(){intn,sum=0,digit=0;scanf("%d",&n);while(n!=0){sum+=n%10;digit++;n/=10;}printf("每位
#include#includeboolisPrime(intn){if(n==1)returnfalse;for(inti=2;i*i