编程输入一个自然数x,求这个自然数的所有约数之和

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

#includevoidmain(){inti,n,k1,k2;n=0;printf("pleaseinputthenumbers\n");scanf("%d%d",&k1,&k2);for(i=k1

1.PrivateSubCommand1_Click()a=InputBox("")Fori=1ToaIfaModi=0ThenPrintiNextEndSub2.PrivateSubCommand1

vari,x,a：integer;beginread(x);a:=0;fori:=1toxdobeginifxmodi=0thena:=a+i;end;write(a);end.

programyueshuhe;varn,i,s:longint;beginwriteln('inputn:');readln(n);s:=1;fori:=2tondobeginifnmodi=0th

#include#includeintfactorial(intn)//计算n!{inti;longsum=1;for(i=1;i=10){if(m%10==0)i++;m/=10;}returni;

只能告诉你算法,pascla不会定义一个变量sum,记录约数之和得到自然数a,定义变量i从1遍历到a,只要a/i==0,sum=sum+i,最后输出sum就是了

publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne

intmain(intargc,char*argv[]){intn,x,y,z;printf("input99

PrivateSubCommand1_Click()DimaAsLongDimiAsLongDimsAsBooleans=Truea=InputBox("请输入一个自然数","输入")'-------

n=1sum=0dowhiln

#includeintmain(){intn,sum=0;printf("请输入一个整数：");scanf("%d",&n);while(n){sum=sum+n%10;n/=10;}printf("

du=度；%输入度值fen=分；%输入分值x=du+fen/60;y=sin(x*pi/180);y

voidmain(){inta[100],i,j;intmax,min,aver;\x05charc;\x05i=0;\x05aver=0;\x05printf("请输入N个数\n");\x05do\

PrivateSubCommand1_Click()DimxAsSinglex=Val(InputBox("请输入第"&i+1&"个所得分数："))Ifx>0ThenMsgBoxx+1/xEndIfE

#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin

给你提供一个思路,定义1,2,3,4,5,6,7,8,9,0,十,百,千,万的拼音,然后按照你的读法把输入的数字先判断是几位数,然后按照规则输出就可以了

importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.

#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing

#include#includeusingnamespacestd;//圆周率constdoublePI=acos(-1);intmain(intargc,char*argv[]){\x05doubl