若x^2-6xy 10y^2 4y 4=0
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![若x^2-6xy 10y^2 4y 4=0](/uploads/image/f/6967076-68-6.jpg?t=%E8%8B%A5x%5E2-6xy+10y%5E2+4y+4%3D0)
x-y=(x-y)(x+y)/(x+y)=(x²-y²)/(x+y)=24/6=4与x+y=6联立2x=10x=5y=6-x=6-5=1x+2y=5+2x1=7如果本题有什么不明白
首先将表达式写成相乘的形式:x^2-y^2+6y=24=>x^2-y^2+6y-9=15=>x^2-(y^2-6y+9)=15=>x^2-(y-3)^2=15=>(x-y+3)(x+y-3)=15又因
2X+3Y-1=X+62X+3Y=7(1)Y-X-8=X+62X-Y=-14(2)(1)+(2)4X+2Y=-7两边除以22X+Y=-7/2
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
1)x²-y²=(x+y)(x-y)6(x-y)=24x-y=42)2m²+4mn+2n²-6=2(m+n)²-6=2*9-6=18-6=123)81
(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x
6x^4y^3+12x^3y^4-24x^2y^5提取6x^2y^3=6x^2y^3(x^2+2xy-4y^3)
(1)已知x+y=6,x²-y²=5,x^2-y^2=(x+y)(x-y)=5x-y=5/(x+y)=5/6(2)若x+y=3,x²+y²=5(x+y)^2=3
x²-y²=24,x+y=6x²-y²=(x-y)(x+y)=24∴x-y=4x+y=6解得:x=5y=1∴x+2y=5+1×2=7.老师讲的,
(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢
3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3
(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)=(x+y)²+2z(x+y)+z²+(x-y)²-z²-2z(x+y)=(x+y)&
X²+Y²+4X-2Y+1=0(X+2)²+(Y-1)²=4由上述方程可知-4≤X≤0X²-6X+Y²-2Y=X²-6X-(X
7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X
若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!
f(x^2-6x)+f(y^2-8y+24)
x(x*x-1)+x(5-x*x)-6y+7=-x+5x-6y+7=2(2x-3y)+7=2*(-4)+7=-8+7=-1再问:能在写详一点吗-x+5x-6y+7再答:x(x*x-1)+x(5-x*x
x^2-y^2=24(x+y)(x-y)=24x+y=6所以x-y=42x-2y=2*4=8