若x² 2y²-2xy 4y 4=0 求x的y次方

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若x² 2y²-2xy 4y 4=0 求x的y次方
若实数x,y满足{2x-y>=0,

这个你用数形结合的方法很简单就可以得出答案,你去画一下他们的可行区域吧,我帮你做了一下答案是b=2

设x>1,y>0,若x^y+x^-y=2根号2,则x^y-x^-y等于

Dx^y+x^-y=2根号2===>(x^y+x^-y)^2=8===>x^2y+x^-2y+2=8===>x^2y+x^-2y=6(x^y-x^-y)^2=x^2y+x^-2y-2=6-2=4==>

若3x-4y=0,则x/y=______,(x-y)/y=______,(3x+2y)/(2x+3y)=_____.

3x=4Y.X/Y=4/3,x-y)/y=(X/Y)-1=1/3,(3x+2y)/(2x+3y)=(4Y+2y)/(8/3y+3y)=18/17(因为3x=4Y,2x=8/3y)再问:若3X-4Y=0

若X,Y互为相反数,且(X+Y+3)(X-Y-2)=0,求X,Y的值?

/>(x+y+3)(x-y-2)=0x,y互为相反数则x+y=0...(1)带入上式3(x-y-2)=0x-y=2...(2)联立(1)(2)得x=1,y=-1

若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=

2x-y-3=3x+2y+1=0,x=5/7,y=-11/7

若2x平方+3xy-2y平方=0,求x+y/x-y

原方程左边=(2x-y)(x+2y)=0所以x=y/2或x=-y/2将x的值分别代入到x+y/x-y得-3或-1/3

若x,y为正数,且2*x+8*y-x*y=0,求x+y的最小值

2*x+8*y-x*y=02x+y8=xy>=2√2x*√8y=4√xy√xy>=4xy>=16x>=16/yx+y>=16/y+y>=2√16/y*√y=8所以最小值是8

若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

1.若2x-3y=0,则x+y/x-y(是个分数额)=( )

由2x-3y=0得:2x=3yx=3y/2把x=3y/2代入(x+y)/(x-y)=(3y/2+y)/(3y/2-y)=(5/2)/(1/2)=5选B由(x-2y)/(3y-x)=2/3得:2(3y-

若3x-5y=0,则x+y/x=(),x-y/y=(),2x-3y/2x+3y=( )

3x-5y=0,则x+y/x=(8/5),x-y/y=(2/3),2x-3y/2x+3y=(1/19)因为3x-5y=0所以3x=5y设x=5,y=3,可以解得3x-5y=0,则x+y/x=(8/5)

若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.

x+y=1x-y=2(x+2y)(x-2y)-(2x-y)(-y-2x)=(x+2y)(x-2y)+(2x-y)(y+2x)=x²-4y²+4x²-y²=5x&

若x^2+y^2-8x-10y+41=0,求x/y+y/x的值

x^2+y^2-8x-10y+41=0x^2-8x+16+y^2-10y+25=0(x-4)^2+(y-5)^2=0所以x=4,y=5x/y+y/x=4/5+5/4=0.8+1.25=2.05

若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于

若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!

若实数x,y满足不等式组x>=0 ,y>=0,x+2y

/>画出可行域.将(x-2)/(y-1)看成是点(x,y)和点(2,1)的两点间的斜率K的倒数.当(x,y)=(0,1/2)时,K取得最小值k=(1-1/2)/(2-0)=1/4当(x,y)=(1,0

若根号x+y-3+绝对值xy+x+y-2=0,求x/y+y/x

有题意得x+y-3>=0xy+x+y-2>=0因为根号x+y-3+绝对值xy+x+y-2=0则x+y-3=0xy+x+y-2=0xy=-1x+y=3x^2+y^2=11x/y+y/x=(x^2+y^2

若2x-3y=0,求5x+4y/3x-2y

2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6

设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y

(线性规划)由条件当X=Y=3时有最大值Z=6即得K=3再由X+2Y>=0很容易求得Z最小值-3

若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&

∵|x+2y-1|+y²+4y+4=0∴|x+2y-1|+(y+2)²=0∴x=5,y=-2(2x-y)²-2(2x-y)(x+2y)+(x+2y)²=[(2x

若不等式组x-y>=0 2x=y=0 x+y

x-y=0和2x+y=2下方,x轴右边当x+y=a分别过原点以及x-y=0和2x+y=2交点(2/3,2/3)时是极限位置其中过原点是三角形过(2/3,2/3)三线共点过原点.a=0,过(2/3,2/