若x的平方减2x加y的平方加6x加10=0-搜答案-百度作业网

应该是x^2-2x+y^2+6y+10=0配方：x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0得x=1y=-3所以x+y=-2

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0(x-1)^2=0x-1=0x=1(y+3)^2=0y+3=0y=-3x+y=1-3=-2

x^2+2x+y^2-6y+10=0可以化解为（x+1)^2+(y-3)^2=0,等价于x+1=0且y-3=0,所以有x=-1,y=3,故x^3*y=-3.

把25拆成16+9(x²-8x+16)+(y²+6y+9)=0(x-4)²+(y+3)²=0平方大于等于0,相加等于0若有一个大于0,则另一个小于0,不成立.所

x^2+2x+y^2-6y+10=0=(x^2+2x+1)+(y^2-6y+9)=0=(x+1)^2+(y^2-6y+3^2)=0=(x+1)^2+(y-3)^2=0x=-1y=3xy=-3

2x^2+3xy=122y^2+3xy=6相减2x^2-2y^2=6x^2-y^2=3（n减2)x的N的绝对值平方家三等于0?

x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2

x2+xy-2y2=0(x-y)(x+2y)=0x-y=0,x+2y=0x=y或x=-2yx=y,则原式=(y2+3y2+y2)/(y2+y2)=5y2/2y2=5/2x=-2y,则原式=(4y2-6

再问：谢了再问：加个朋友

0＜y＜x【(x^2+y^2)(x-y)】-【(x^2-y^2)(x+y)】=【(x^2+y^2)(x-y)】-【(x-y)(x+y)^2】=(x-y)【(x^2+y^2-(x+y)^2】=(x-y)

x的平方减6xy加9y的平方减2x加6y加1=(x-3y-1)^2

6x加2x的平方减3x加x平方加1=3x^2+3x+1,代入X＝－5时,其值＝61

问题求什么?再问：求x加y的值再答：x^2-2x+1+y^2-6y+9=0(x-1)^2+(y-3)^2=0x=1y=32x+3y=11

x+y-2=x^2+axy+by^2-5x+y+6x+y-2是x^2+axy+by^2-5x+y+6的因式当x+y-2=0时,x^2+axy+by^2-5x+y+6=0令x=y=1,x+y-2=0x^

x^2-4xy+4y^2-3x+6y+2=(x-2y)^2-3(x-2y)+2=(x-2y-1)(x-2y-2)

x^2+4x+y^2-2y+5=0(x^2+4x+4)+(y^2-2y+1)=0(x+2)^2+(y-1)^2=0x=-2,y=1x^2+y^2=(-2)^2+1^2=4+1=5

x^2-2x+y^2+8y+17=0(x-1)^2+(y+4)^2=0x=1;y=-4;

4

(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!

x²+y²=x²-xy+y²+xy=3+5=82x²+xy+3y²=2x²-2xy+3y²+3xy=2(x²-