若圆x²+y²-6x+6y+14=0关于直线

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/01 05:00:03
若圆x²+y²-6x+6y+14=0关于直线
计算(4x^2-2x^3+6x)/(-2x)-(x-1)^2y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/

原式=-2x+x^2-3-x^2+2x-1=-4原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)=(y-2)/(y-3)+(y+2)/(y+1)=(y^2-y-2+y^2-y-

9(x-y)^2-6(y-x)^2+1

9(x-y)^2-6(y-x)+1=9(x-y)^2+6(x-y)+1=[3(x-y)+1]^2=(3x-3y+1)^2

因式分解3x^2(x-y)+6x(y-x)

3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)

计算:(x-y)^2*(y-x)^2*(x-y)^6

(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x

(x-y)³+9(x-y)-6(x-y)²

原式=(x-y)[(x-y)^2-6(x-y)+9]=(x-y)(x-y-3)^2很高兴为您解答,祝你学习进步!不懂可追问!

-(-1/3x+y)+(1/6x-y)

1,x/3-y+x/6-y=x/2-2y2,上面提出ab,然后和分母约去ab得:-2(a^2-3ab-2b^2)3,直接乘出来:2x^2+3x-2x-3=2x^2+x-34,平方差公式:(2a+b)^

已知x²+y²-4x+6y+13=0,求x,y的值

解题思路:由完全平方公式、非负数的和等于0,可解。、解题过程:已知x²+y²-4x+6y+13=0,求x,y的值解:x²+y²-4x+6y+13=0x²-4x+4+y²+6y+9=0(x-2)²+(y

已知,x²-4x+9y²+6y+5=0,求x+3y的值

解题思路:对于这种等式一定可以化成平方相加的形式,这里面要使用到完全平方公式。解题过程:

(x-y)x^6+(y-x)y^6因式分解

(x-y)x^6+(y-x)y^6=(x-y)x^6-(x-y)y^6=(x-y)(x^6-y^6)=(x-y)(x³+y³)(x³-y³)=(x-y)(x+y

6(x+y)2-2(x-y)(x+y)因式分解

(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢

(x+y)²+x+y-6因式分解

原式=(x+y)²+(x+y)-6=(x+y+3)(x+y-2)

(三分之二x√9x +6x√x/y)+(y√y/x -x²√x/1)

y/x哪个是分子?按理说y/x应该是x分之y,即y是分子再问:x是分子啊二次根式化简。。。。再答:注意应是分子/分母分子在前面的我前面都是按这个做的显然x>0,y>0则原式=(2x/3)*3√x+6x

已知x平方-6x+9与/y-1/互为相反数,计算(x/y-y/x)÷( x+y)

x平方-6x+9与/y-1/互为相反数(x-3)²+|y-1|=0x-3=0y-1=0x=3y=1(x/y-y/x)÷(x+y)=(3-1/3)÷(3+1)=2/3

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

已知x²+9y²-4x+6y+5=0,求x²y³的值

解题思路:先利用完全平方公式求出x、y的值,再代入求出代数式的值。解题过程:

9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y的平方(x-y)(x+1),因式分解

第一项与第三项先合并9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y^2*(x-y)(x+1)=(x-y)(x+1)(9xy+6y^2)-3y(x-y)(3x+2y)=(x-y)(x+1

计算:(2/3x√9x+6x√y/x)+(y√x/y-√1/x)

(2/3x√9x6x√y/x)(y√x/y-x²√1/x)=2/3*x*3√x6x*√(xy)/xy*√(xy)/y-x²√x/x=2x√x6√(xy)√(xy)-x√x=x√x7

1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y)

1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)

{4/(x+y)+6/(x-y)=3 {9/(x-y)-1/(x+y)=1

完整设1/(x+y)=a,1/(x-y)=b原方程组可变为4a+6b=39b-a=1a=9b-136b-4+6b=3b=1/6,a=1/2x+y=2x-y=6所以原方程组的解为:x=4,y=-2