解方程2x³ 3x²-11x-6=0
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24x=140-4x28x=140x=5
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
x(x-3)=6-2xx²-3x=6-2xx²-x-6=0(x-3)(x+2)=0x1=3x2=-2
两边乘(x+3)(x-2)6x+18=x²-2x-x²-x+66x+18=-3x+69x=-12x=-4/3经检验,x=-4/3是方程的解
解x(6-x)-2x(x+1)-(x³-3x^4)/x²=46x-x²-2x²-2x-(x-3x²)=44x-3x²-x+3x²=
((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30
我给个思路吧(X+2-1/X+2)-(X+3-1/X+3)=(X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决
是X/(X-2)-(1-X^2)/(X^2-5X+6)=2X/(X-3)吗?首先因式分解(X^2-5X+6)=(X-2)(X-3),显然X不等于2且X不等于3,所以等式两边同乘以(X-2)(X-3)得
令2x-11=0,得x=11/2令x-3=0,得x=3令x-8=0,得x=8当x
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
(x-2)(3x-3)=0x=2或x=1
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x
通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
(x-3分之x)+(x^2-3x分之x+6)=x分之x-3x/(x-3)+(x+6)/x(x-3)=(x-3)/x两边同乘以x(x-3)x²+x+6=x²-6x+97x=3x=3/
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你
解方程:(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开:X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得:12x=18则x=18/12=3/2