设方程x²y-2xz e²=1确定隐函数z=z(x,y),求zx,zy
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xy+e^y=y+1(1)求d^2y/dx^2在x=0处的值:(1)两边分别对x求导:y+xy'+e^yy'=y'y/y'+x+e^y=1(2)(2)两边对x再求导一次:(y'y'-yy'')/y'^
x^2+y^2-8x-6y+21=0配方,有:x^2-8x+16+y^2-6y+9=4(x-4)^2+(y-3)^2=4这是一个以(4,3)为圆心,2为半径的圆令x-4=2sinay-3=2cosa(
d(y^2)/dx=d(y^2)/dy*dy/dx=2y*dy/dx这个复合函数求导法则正如ovtr0001仁兄所说那样,你可以翻翻课本这个……还要详细点呀?你有书么?你看书那里不懂可以提出来,我可能
用换元法解方程6x^2+4x+1/3x^2+2x=3,设3x^2+2x=y,则原方程变形为(2y+1)/y=3
1)y|x=o当x=0时sin(0)-1/y-0=1得:y|x=0=-1(2)y'|x=osin(xy)-1/y-x=1两边对x求导:cos(xy)(y+xy')+y'/y^2-1=0当x=0时y=-
把x-1x=y代入原方程得:y2-3y+2=0.故选D.
x+y=ay=a-x代入2x²+3a²-6ax+3x²-6a+6x=05x²+(6-6a)x+(3a²-6a)=0x是实数所以△>=036-72a+3
两边对x求导2x+2y*dy/dx=0dy/dx=-x/y有不明白的追问再问:刚学不太明白,2x+2y*dy/dx=0里的dy/dx哪来的,是y'吗?再答:是的复合函数求导注意这里y是x的函数不妨换个
设x^2/x+1=y,则原方程可化为6/y+y=7
ln(x²+y²)=x+y-1两边对x求导得:(2x+2yy')/(x²+y²)=1+y'整理得:y'=(2x-x²-y²)/(x²
分别对y求导,求左边为1+【e^(x+y)×(dx/dy+1)】右边为2×dx/dy推的dx/dy:自己算下,没得草稿纸.
(x/x-1)-(2x-2/x)-1=0(x/x-1)-2(x-1)/x-1=0设(x/x-1)=y则y-2/y-1=0两边乘yy^2-y-2=0(y-2)(y+1)=0y=2或y=-1则x/x-1=
请问是2x/(x2-1-3x2)-3/x=2还是2x/(x2-1)-3x2-3/x=2,2x/(x2-1)-(3x2-3)/x=2再问:2x/(x2-1)-(3x2-3)/x=2再答:不好意思,刚刚看
2y^2-4y+1=0还得附加条件y不等于0?
用换元法解方程3x^2/(x+1)-(x+1)/x^2=2,可以设_x²/(x+1)__=y,那么得到关于y的整式方程是:3y-1/y=2
ln(x+y)=x·lny(1+y‘)/(x+y)=lny+x/y·y‘y+y·y‘=y(x+y)lny+x(x+y)·y‘y‘=【y(x+x)lny-y】/【y-x(x+y)】再问:лл����
∵x^-1/x-x/x^-1+2=0y=x^-1/x∴x^-1/x=yx/x^-1=1÷(x^-1/x)=1/y则原式=y-1/y+2=0