输入n,输出Fibonacci数列前n项程序

#include<stdio.h>intfib(inti)     //用递归来实现{ if(i==1||i==2) 

#includeintmain(){intf1=1,f2=1;inti;for(i=1;i

好像ACM的题哦.#includevoidmian(){intn;scanf("%d",&n);if(n%2==0){printf("%diseven",n);}else{printf("%disod

while(m>=1&&n

#include#includeintfib(intn){\x09inti,*A;\x09A=(int*)malloc(sizeof(int)*n);//动态申请内存\x09A[0]=1;A[1]=1

#includeintfib(intn);intmain(void){\x05intm,n,i,j;\x05printf("Inputm:\n");\x05scanf("%d",&m);\x05pri

//Author:Yach//QQ:79564727//申请请注明来者何人..#includeusingnamespacestd;intfib(int);voidmAndn(int,int);intf

这是数学题?!确定不是程序设计...1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,搞定,希望没算错...其实斐波

斐波那契的数学函数如下：在此提供javascript语言实现.<script>function fibonacci(n){  var fx=[0,1

#includeintmain(){float*p,*q,*max,*min,ave=0;intn;scanf("%d",&n);q=(float*)calloc(n,sizeof(float));f

#includeintfib(intn){if(1==n||2==n)return1;returnfib(n-1)+fib(n-2);}intmain(){inti,n;scanf("%d",&n);

Private Sub Form_Load()Dim I As IntegerForm1.AutoRedraw = TrueFor

#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N：\n");scanf("%d",&N);printf("请输入N个整数：\n

#includemain(){intn,i,j,k;while(scanf("%d",&n)==1){if(n==1||n==2){printf("%d\n",1);cont

经鉴定,LZ对于C语言中的数组/指针以及函数的相关知识点还没掌握好这一题的正确思路应该是,设计一个函数intfeibo(intn),该函数的作用是返回斐波那契数列第n项的值.主函数中获取用户输入的N,

inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=

#include#includeintmain(){inta,b,c,d;scanf("%d",&a);d=a;for(b=2;

#include#includeintn=0;intnum=0;intmin=0;inti=0;intmain(void){\x09printf("请输入n:\n");\x09scanf("%d",&

datasegmentmsgdb'inputN:$'dataendscodesegmentassumecs:code,ds:datamainprocnearstart:movax,datamovds,

#include　　usingnamespacestd;　　intmain(){　　//该程序虽然能通过评测系统的检测,但时间复杂度为O(n^3),因而有待改进　　intN;//矩阵阶数　　in