VB题,产生20个20~40之间的两位随机整数,统计不同数据出现的次数

Dima%(1To20)Fori=1To20a(i)=Int(Rnd*90+10)Printa(i);NextPrintFori=1To20Ifa(i)Mod2=1ThenPrinta(i);EndI

试一下：PrivateSubCommand1_Click()Dimarr(1To20),iFori=1To20Randomizearr(i)=Int(Rnd*101)NextfcarrPrintJoi

窗体中加命令按钮,单击事件代码如下：PrivateSubCommand1_Click()  Randomize  Dima(1To20)AsInteger&nb

dima,max,min,sum,averagesum=0max=20min=50fori=1to20a=(Rnd*50)+50sum=sum+aifamaxthenmax=aprintanextpr

PrivateSubForm_click()Dimn(1To20)AsIntegerDimi,j,ave,tempRandomizeFori=1To20n(i)=Int((51*Rnd)+50)Pri

Dima(1To20)AsIntegerPrivateSubCommand1_Click()ClsScale(0,0)-(100,100)Foru=1To20a(u)=Int(Rnd*50)+50b=

PrivateSubForm_Click()Dima(19)AsIntegerDimmaxAsInteger,minAsInteger,avAsIntegerFori=0To19a(i)=Int((1

PrivateSubCommand1_Click()RandomizeDima(1To10)Dimmax,min,avemin=50:max=20Fori=1To10a(i)=Int(Rnd*21+3

PrivateSubCommand1_Click()DimIAsInteger,NAsInteger,MaxAsInteger,MinAsIntegerMin=100RandomizeForI=1To

利用Rnd函数产生随机数的范围为：Int（(上限-下限+1)*Rnd)+下限

PrivateSubCommand1_Click()ClsDimmArr%(1To20),Max%,Min%,sum%,i%Max=50Min=100Fori=1To20RandomizemArr(i

privatesubcommand1_click()dimjs,os,i,afori=1to20a=int(Rnd*99)+1ifamod2=0thenjs=js+ielseos=os+inextpr

'窗体放一个按钮Command1PrivateSubCommand1_Click()Randomize'初始化随机数生成器DimJiShuHangAsString'奇数行DimOuShuHangAsS

再问：谢了，能否把程序给提供一下，我不会再答：好吧！

PrivateSubCommand1_Click()RandomizeFori=1To20a=Int(Rnd()*21+30)Printa;IfiMod4=0ThenPrintNextEndSub这里

产生2~99之间的1次1个随机数randomizeInt((99-2)*Rnd+1)产生1~n之间的1次20个随机数RandomizeDimtemAsInteger,jAsInteger,iAsInt

subform_click()dima%(20)fori=1to20a(i)=int(rnd()*10+1)printa(i),nextendsu

楼主看看这个：Private Sub Command1_Click()   Dim aNum(19) As Long,&

Private Sub Command1_Click()    Dim a%(0 To 19), b

PrivateSubCommand1_Click()DimZs(1To35)AsIntegerFori=1To35RandomizeZs(i)=Int(61*Rnd)+20PrintZs(i);Nex