xy除以x^2 y^2,当x y趋0,的极限-搜答案-百度作业网

由X+Y=3XY可得X+Y-XY=2XY,用X+Y-XY替换分母中的2XY,所以(2X+2Y-XY)/(X+Y+2XY)=(2X+2Y-XY)/(2X+2Y-XY)=1

[XY(2X-Y)的平方-(-XY的二次方)的二次方]除以8XY=[(2x-y)²-xy³]÷8=[（-2/3-1）²+1/3*1]÷8=（25/9+1/3）÷8=28/

原式=(x+y)(x-y)/(x+y)²×2x(x+y)/(x+2y)=(x-y)/(x+y)×2x(x+y)/(x+2y)=2x(x-y)/(x+2y)=(2x²-2xy)/(x

对.前提是x不等于y

【x的平方-2x】除以2y-xy=x(x-2)/[-y(x-2)]=-x/y

因为x+y除以xy等于4,所以,x+y=4xy2x-5xy+2y=2(x+y)-5xy=2*4xy-5xy=3xyx+2xy+y=4xy+2xy=6xy所以,2x-5xy+2y除以x+2xy+y的值＝

由于xy除以x+y=2故xy=2（x+y）将这代入8x-5xy+8y除以-x+3xy-y化简得其中的（x+y）会相互约去故8x-5xy+8y除以-x+3xy-y=-2/5希望这个能帮到你over~

9x^2/2y再问：貌似是负的吧再答：没看见前面的“负”…………

1.∵x²+y²≥2|xy|∴0≤|(x+y)/(x²+y²-xy)|=|x+y|/|x²+y²-xy|≤|x+y|/(x²+y&

3xy-[2xy-2(xy-2分之3xy)+xy]+3xy=6xy-[2xy-2xy+3xy+xy)=6xy-4xy=2xy=2×3×3分之1=2

原式=[4(x+y)-2xy]分之[(x+y)+xy]=[4(3xy)-2xy]分之[(3xy)+xy]=10xy分之2xy=5分之1

x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)

=3xy×(-3x/2y)=-9x²/2

原式=1÷2×√[xy/(y²/x)]=1/2×√(x²y/y²)=x√y/(2y)

x=2013,y=2013[3x(x²y-xy²）+xy×（3xy-2x²）]/(x²y)=[3x²y(x-y）+x²y×（3y-2x）]/

由题意得：xy=3（x+y）原式=[2x+2y-9(x+y)]%[-x-y+9(x+y)]=[-7(x+y)]%[8(x+y)]=-7/8(因为x+y不等于0)

（xy-x²）÷xy分之x²-2xy+y²乘x²分之x-y=-x(x-y)×xy/(x-y)²×(x-y)/x²=-y∴结果与x的值没有关系

因式分解原式=[x(x-2)]/[-y(x-2)]=-x/y

原式即为A*(x+2y)^2/(x-y)(x+y)=1即A*16/3=1∴A=3/16很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+