x^3*(x^2 1)^(1 2)

4.66666719.402985第三个方程如果两个代数式之间是减号的话,方程不成立,既无解,

这是两道题吗?1、两边同时乘(x-1)(x-2)(x-3）答案是x1=-1,x2=22、分母因式分解分别为(x-7)(2x+3)和(x-5)(x-7)然后同时乘(x-5)(x-7)(2x+3)答案是x

=x^18+x^15+x^12+x^9+x^6+x^3+1+x^3-1+5-4分解因式把下面的18换成21就是了=(x^18+1)+(x^15+1)+(x^12+1)+(x^9+1)+(x^6+1)+

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0

M大于2小于等于3

1.4(x+5)(x+6)(x+10)(x+12)－3x^2=4*[(x+5)(x+12)][(x+6)(x+10)]-3x^2=4*(x^2+60+17x)(x^2+60+16x)-3x^2=4*[

每个绝对值里都是正数所以原式=x+1+x+3+x+5+……+x+13-x-2-x-4-x-6-……-x-12=x-1*6+13=x+7=π/2+7

x平方-6x+8=x²-2×3x+9-9+8=（x-3）²-1=（x-3-1）（x-3+1）=（x-4）（x-2）x平方+x-6=（x-2）（x+3）12+x-x平方=（4-x）（

看清楚了,是不等式组.把你的答案合并下第一题：X>3第二题：X>1第三题：无解(我不知道你大于负六怎么出来的!)第四题：2

题目应是1/(x^2+x﹚+1/(x^2+3x+2﹚+1/(x^2+5x+6﹚+1/(x^2+7x+12﹚=4/211/x(x+1﹚+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)

(x-2)(x-3)+2(x-5)(x+6)-3(x^2-7x+12)=x^2-5x+6+2x^2+2x-60-3x^2+21x-36=18x-90=18*(-5/2)-90=-45-90=-135

1.求x^21+x^15+x^12+x^9+x^6+x^3+1被x^2+x+1除所得的余式答：原式=[x^21+x^18-x^18-x^15+2*x^15+2*x^12-x^12-x^9+2*x^9+

应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x

原式化简：{（x-3)(x-2)/(x-3)(x-4)}²÷{(x+1)(x+2)/(x-4)(x+2)}²{(x-2)/(x-4)}²÷{(x+1)/(x-4)}

①x8x1(x+8)(x+1)②x-3x-3(x-3)^2③x3x-4(x+3)(x-4)④x3x7(x+3)(x+7)⑤x5x-25(x+5)(x-25)⑥x12x3(x+1)(2x+3)

分步写,好让看的清楚符号[√(x^2-6x+9)/x^2-x-12]=√(x-3)^2/(x-4)(x+3）=（x-3)/(x-4)(x+3）；(x^3-16x)/(x^2-3x)=x(x^2-16)

x^3+x-30(分解因式)=(x^3-27)+(x-3)=(x-3)(x^2+3x+9)+(x-3)=(x-3)(x^2+3x+9+1)=(x-3)(x^2+3x+10);x^12-y^12;=(x

(x×x+3x+2)(x×x+7x+12)-24=(x+1)(x+2)(x+3)(x+4)-24=(x+1)(x+4)(x+2)(x+3)-24=(x²+5x+4)(x²+5x+6

1.3x乘x-7x+1=0x^2-7/3x=-1/3(x-7/6)^2=49/36-1/3x=7/6±√37/62.12x乘x-8x-21=0x^2-3/4x=7/4(x-3/8)^2=7/4+9/6