百度作业网求大神级商务统计学高手,最好用英文作答
来源：学生作业帮 编辑：百度作业网作业帮 分类：英语作业 时间：2024/06/12 14:43:48
求大神级商务统计学高手,最好用英文作答
1.The mean number of sales enquity calls received per day at a drill factory is 126.5; what is the probability that excatly 110 calls will be received tommorrow?
2.in the past,23% of callers making enquiries went on to place an order.Of those who placed an order,32% accepted a sample first.Of course who didn't go on to place an order,18% accepted a sample.A caller has just declined a sample; what is the probability that he will place an order?
3.what is the probability that an individual caller accepts a sample?
4.Draw a Wenn diagram,with areas proportional to probability,representing the outcomes described in 2 and 3
5.If 100 people call,what is the probability that exactly 25 of them accept a sample?
6.If the values of orders placed are approximately normally distributed with a mean value of RMB 122,000 and a standard deviation of RMB 28,000,what proportion of orders have values of more than RMB 200,000?
7.Sketch a standardised normal distribution curve and mark on it the Z values representing the values from 6
1.The mean number of sales enquity calls received per day at a drill factory is 126.5; what is the probability that excatly 110 calls will be received tommorrow?
2.in the past,23% of callers making enquiries went on to place an order.Of those who placed an order,32% accepted a sample first.Of course who didn't go on to place an order,18% accepted a sample.A caller has just declined a sample; what is the probability that he will place an order?
3.what is the probability that an individual caller accepts a sample?
4.Draw a Wenn diagram,with areas proportional to probability,representing the outcomes described in 2 and 3
5.If 100 people call,what is the probability that exactly 25 of them accept a sample?
6.If the values of orders placed are approximately normally distributed with a mean value of RMB 122,000 and a standard deviation of RMB 28,000,what proportion of orders have values of more than RMB 200,000?
7.Sketch a standardised normal distribution curve and mark on it the Z values representing the values from 6
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