函数y=cos(2x+π/4) 求dy
设函数y=e^2x+cos x求倒数y'与微分dy
由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2)
函数y=cos ln(x^2+e^-x) ,求dy
y=(1+x^4)^cos x,求dy
已知y=cos^4(2x+π/3),求dy/dx
设y=cos^2(x+1),求dy
设e^(x+y)+cos(xy)=0确定y是x的函数求dy
ysinx+cos(x-y)=0,求dy/dx|(x=π/2)
设函数y=y(x)由方程cos(x+y)+y=1确定,求dy/dx
由方程cos(x+y)+e^y=x确定y和x的隐函数,求dy
高数复合函数求导 y=ln cos e^x,求dy/dx
cos(x+y)+y=1 求dy/dx