对数方程问题log[(4-x),(x^2-2x)]=log[(4-x),(5x-6)]的根有?我把右边移过去,然后合体,

对数的运算问题-log a 1/x=-(log a 1-log a x)=log a x 求函数f(x)=-(log二分之一为底X对数)^2-log四分之一为底X的对数+5在区间【2,4】上的值 [( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log( 对数不等式：log(1/2) (4x^2-x)>1 log(2x-1) 为底(5x+2)的对数=log(2x-1)为底(x^2+6)的对数 4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] 2 log(3x)= log 4 +log(6-x)怎么求...急 log以4为底(x+12)的对数乘以log以x为底2的对数等于 log以a为底(x-4)的对数>log以a为底(2x-1)对数 解方程x^log(2) (x)=4