∫cos^4x/sin^3x dx=?

来源：学生作业帮编辑：百度作业网作业帮分类：数学作业时间：2024/04/29 18:21:46

∫cos^4x/sin^3x dx=?

∫(cosx)^4dx/(sinx^3)=∫(cosx)^3dsinx/sinx^3=(-1/2)∫cosx^3d(1/sinx^2)
=(-1/2)cosx^3/sinx^2-(3/2)∫(1-sinx^2)dx/sinx
=(-1/2)cosx^3/sinx^2-(3/2)cosx+(3/4)ln|(1+cosx)/(1-cosx)|+C
楼上的正负号弄错了

∫ sin^4(x)cos^3(x)dx ∫sin^3(x)cos^2(x)dx= 定积分∫(-π/2,π/2)(cos^4x+sin^3x)dx= ∫sin(x) cos^2(x)dx 求∫1/(sin^4x+cos^4x)dx, ∫sin^(3)x cos^(3)x dx 求微积分 ∫sin^2(x)cos^4(x) dx ∫[1/(sin^2(x)cos^4(x)]dx ∫dx/cos^2X+4sin^2X ∫sin(7x)cos(10x)dx=? 微积分求解：∫sin^3 (x) cos^2 (x) dx 求不定积分：∫(sin x/cos^3 x)dx