z=f(x,x/y)求二阶偏导a∧2z/ax∧2
设z=f(xy,y/x),其中f具有二阶连续偏导数,求a^2z/ax^2,a^2z/axay.
分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y)
设函数z=f(x,x/y),f具有二阶连续偏导数,求az/ax,a^2z/axay
由方程z=f(x,y∧2,z)所确立的函数z=z(x,y)的全微分是什么
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z
设z=f(xy,x+y),且f有连续的二阶偏导数,求a^2z/axay
3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz=
x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)
求函数Z=ln(x^2+y^2)的偏导数az/ax...和a^2z/ax^2
设函数f(x)=ax+1/x+b(a,b属于Z)曲线y=f(x)在点(2,f(2))处的切线方程为y=3.证明曲线y=f
设函数f可微,z=f(ye^x,x/(y^2)) 求z/x,z/y
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x