1/x的平方+3x+2+1/x的平方+5x+6+1/x的平方+4x+3
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1/x的平方+3x+2+1/x的平方+5x+6+1/x的平方+4x+3
![1/x的平方+3x+2+1/x的平方+5x+6+1/x的平方+4x+3](/uploads/image/z/16646552-8-2.jpg?t=1%2Fx%E7%9A%84%E5%B9%B3%E6%96%B9%2B3x%2B2%2B1%2Fx%E7%9A%84%E5%B9%B3%E6%96%B9%2B5x%2B6%2B1%2Fx%E7%9A%84%E5%B9%B3%E6%96%B9%2B4x%2B3)
1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)
=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+1)(x+3)
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+1)(x+3)
=1/(x+1)-1/(x+3)+1/(x+1)(x+3)
=(x+3)/(x+1)(x+3)-(x+1)/(x+1)(x+3)+1/(x+1)(x+3)
=[(x+3)-(x+1)]/(x+1)(x+3)+1/(x+1)(x+3)
=2/(x+1)(x+3)+1/(x+1)(x+3)
=3/(x+1)(x+3)
=3/(x^2+4x+3)
=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+1)(x+3)
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+1)(x+3)
=1/(x+1)-1/(x+3)+1/(x+1)(x+3)
=(x+3)/(x+1)(x+3)-(x+1)/(x+1)(x+3)+1/(x+1)(x+3)
=[(x+3)-(x+1)]/(x+1)(x+3)+1/(x+1)(x+3)
=2/(x+1)(x+3)+1/(x+1)(x+3)
=3/(x+1)(x+3)
=3/(x^2+4x+3)
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