j计算x ^2-(4x+5y)(-5y+4x)+(-2x-7y)^2
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)
x^8-x^7y+x^6y^2-x^5y^3+x^4y^4-x^3y^5+x^2y^-xy^7+y^8
方程组3x+2y=5 5x+4y=7 j加减消元法
先化简,后求值(x+5y)(x+4y)(x-y)(x+y),其中,x=-2又2/3,y=3/7,用公式计算
3x+2=y 5X+4=Y 7X+6=Y 9X+8=y 11x=y要如何计算
方程式计算5X-2=Y 4X+3=Y 求X.Y
计算:(x+y)^2×(-x-y)^3×[-3/4(x-y)^3]×5/6(y-x)^2
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8
1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y
计算(x-2y)^2-4(2x+y)(y-2x)+4x(y-2)
计算【3(x-y)^2(x+y)^-2/4(x+y)^2(x-y)^-2】^-2