一个简单编程题#include#includeint main(){int n,i=1,m=1;double x,s=0

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一个简单编程题
#include
#include
int main(){
int n,i=1,m=1;double x,s=0;
scanf("%d%d",&x,&n);
while(i

我帮你编两个函数吧,调用请自己琢磨下.
double fact(int n)
{
double m = n;
if(n < 2) return 1;
return m * fact(n - 1);
}
double mypow(double x, int n)
{
double y = 1.0;
for (int i = 0; i < n; i++) y *= x;
return y;
}
提示：循环时可用：
s += mypow(-1, i-1) * mypow(s, i) / fact(i);

#includeint main(void){int x,y,t,n,flag=1,s,i;while( scanf(" 求pi的近似值#include #include void main() { int i=1; double sum=0 一个简单的程序题#includeint main(void){int x=20;printf("%d",0 #include int main(){inti,n=20;double a=2,b=1,s=0,t;for(i=1;i #include main() {double x=1.0; int n; for(n=0;n #include void main() {int a=1,m,n,j,s=0; #include#include#includeint main(){long int x1=123456789;lon #includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a 英语翻译#include void main() { double x = 1,y = 2; double s = 0; 新手表示看不懂#includeint isZhengshu(double m,int n){int j;for(j=0; # include # include int mian () { int m,n,i,s=0; int a[10000 #include int main( ) { int a ,b,m ,n ; m = n = 1 ; scanf( "%