1:(ab+cd)(a²-b²+c²-d²)+(ac+bd)(a²+b
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1:(ab+cd)(a²-b²+c²-d²)+(ac+bd)(a²+b²-c²-d²)
2:x四次方+2000x²+1999x+2000
3:x²+xy-6y²+x+13y-6
4:x²-2xy+y²-3y+2
2:x四次方+2000x²+1999x+2000
3:x²+xy-6y²+x+13y-6
4:x²-2xy+y²-3y+2
1:(ab+cd)(a²-b²+c²-d²)+(ac+bd)(a²+b²-c²-d²)
= (ab+cd)(a²-d²)+(ab+cd)(c²-b²)+(ac+bd)(a²-d²)+(ac+bd)((b²-c²)
= (a²-d²)(ab+cd+ac+bd)+(b²-c²)(ac+bd-ab-cd)
=(a-d)(a+d)²(b+c)+(b+c)(b-c)²(d-a)
=(a-d)(b+c)[(a+d)²-(b-c)²]=(a-d)(b+c)(a+d+b-c)(a+d-b+c)
2:x^4+2000x²+1999x+2000=x^4-x+2000(x²+x+1)
=x(x^3-1)+2000(x²+x+1)=(x²+x+1)[x(x-1)+2000]=(x²+x+1)(x²-x+2000)
3:x²+xy-6y²+x+13y-6=(x-2y)(x+3y)+x+13y-6=(x-2y+3)(x+3y-2)
4:x²-2xy+y²-3y+2=
第四题是否有误,请校对!
= (ab+cd)(a²-d²)+(ab+cd)(c²-b²)+(ac+bd)(a²-d²)+(ac+bd)((b²-c²)
= (a²-d²)(ab+cd+ac+bd)+(b²-c²)(ac+bd-ab-cd)
=(a-d)(a+d)²(b+c)+(b+c)(b-c)²(d-a)
=(a-d)(b+c)[(a+d)²-(b-c)²]=(a-d)(b+c)(a+d+b-c)(a+d-b+c)
2:x^4+2000x²+1999x+2000=x^4-x+2000(x²+x+1)
=x(x^3-1)+2000(x²+x+1)=(x²+x+1)[x(x-1)+2000]=(x²+x+1)(x²-x+2000)
3:x²+xy-6y²+x+13y-6=(x-2y)(x+3y)+x+13y-6=(x-2y+3)(x+3y-2)
4:x²-2xy+y²-3y+2=
第四题是否有误,请校对!
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