cos2x=3/5.sin^4+cos^4x=?
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/
已知函数f(x)=(6cos^4x+5sin^2x-4)/cos2x
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
解下列方程 cos2x=cosx+sinx sin^4x-cos^4x=cosx+sinx
设f(x)=(sin^4 x-cos^4 x-5)/(cos2x+2). (a)证明f(x)= 3/(2 sin^2 x
已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
根据下列条件求函数f(x)=sin(x+∏/4)+2sin(x-∏/4)-4cos2x+3cos(x+3∏/4)的值 (
已知cos2X=根号2/3,则sin^4X+cos^4的值为?求详细过程!
已知函数f(x)=(6cos^4x+5sin^2x-4)/cos2x 判断f(x)的奇偶性
已知cos(π/4+x)=5/13,0<x<π/4,求sin(π/4-x)/cos2x
已知sin(π/4-x)=5/13,x属于(0,π/4),求(cos2x)/cos[(π/4)+x]