一直3x+7y+z=3.15
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知3x+7y+z=3.15,4x+10y+z=4.2求x+y+z的值 将原方程组整理得2(x+3y)+(x+y+z)=
matlab里面 请问f=@(x,y,z)(1+y)*z.^y-(-0.25*(x-1)^2+0.25)^x.; 一直出
已知方程组 3x+7y+z=3.15 4x+10y+z=4.20 求x+y+z的值
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x+2y-z=1 3x-3y+z=2 3x+3y+z=7
已知3X+7Y+Z=6 4X+10Y+z=7 求X+Y+Z=?
x+2y+3z=14 2x+y+z=7 3x+y+2z=11
解方程:{2x+3y+z=7,x+y+z=4,3x+y-z=-4
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?
3x+7y+z=5 ,4x+10y+z=6 ,x+y+z=
x+2y+4z=17 2x+y+z=7 3x+y+2z=11