sina+cosa-1)(sina-cosa+1)/sin2a
化简(sina+cosa-1)(sina-cosa+1)/sin2a
证明sin2a/(1+sina+cosa)=sina+cosa-1
sin2a+sina/cos2a+cosa+1=
(2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)
三角函数的正切求证题1.(1+sin2A)/(cosA+sinA)=cosA+sinA 2(1-sinA*cosA)/c
证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
求证:1+sina+cosa/1+sina-cosa+1-cosa+sina/1+cosa+sina=2/sina
化简 [sin2a/(1+cos2a) ][cosa/(1+cosa)][sina/(1-cosa)]=
证明(sin2a/1-cos2a)*(cosa/1-sina)=1+sina/sina
已知根号2-cosa/sina=1,则sin2a=
若sina+cosa=1/5,sin2a=?
(sina-cosa)^2=1-sin2a怎么证明,