将1到11这11个数字分组,使得每组的和相等,问有多少种分法.

将1到11这11个数字分组,使得每组的和相等,问有多少种分法.

71种
再问： 我要的不是答案，是过程，方法，思路。。。
再答： 我检查了一遍多算一个 应该是70种可能，如下： 分6组共1种可能： (11),(10,1),(9,2),(8,3),(7,4),(6,5) 分3组共36种可能 (11,10,1),(9,8,5),(7,6,4,3,2) (11,10,1),(9,8,3,2),(7,6,5,4) (11,10,1),(9,7,6),(8,5,4,3,2) (11,10,1),(9,7,4,2),(8,6,5,3) (11,10,1),(9,6,4,3),(8,7,5,2) (11,9,2),(10,8,4),(7,6,5,3,1) (11,9,2),(10,8,3,1),(7,6,5,4) (11.9.2),(10,7,5),(8,6,4,3,1) (11,9,2),(10,7,4,1),(8,6,5,3) (11,9,2),(10,6,5,1),(8,7,4,3) (11,8,3),(10,9,2,1),(7,6,5,4) (11,8,3),(10,7,5),(9,6,4,2,1) (11,8,3),(10,7,4,1),(9,6,5,2) (11,8,3),(10,6,4,2),(9,7,5,1) (11,8,3),(10,6,5,1),(9,7,4,2) (11,7,4),(10,9,3),(8,6,5,2,1) (11,7,4),(10,9,2,1),(8,6,5,3) (11,7,4),(10,8,3,1),(9,6,5,2) (11,7,4),(10,6,5,1),(9,8,3,2) (11,6,5),(10,9,3),(8,7,4,2,1) (11,6,5),(10,9,2,1),(8,7,4,3) (11,6,5),(10,8,4),(9,7,3,2,1) (11,6,5),(10,8,3,1),(9,7,4,2) (11,6,5),(10,7,4,1),(9,8,3,2) (11,6,5),(10,7,3,2),(9,8,4,1) (11,8,2,1),(10,9,3),(7,6,5,4) (11,8,2,1),(10,7,5),(9,6,4,3) (11,8,2,1),(10,5,4,3),(9,7,6) (11,7,3,1),(10,8,4),(9,6,5,2) (11,7,3,1),(10,6,4,2),(9,8,5) (11,6,4,1),(10,9,3),(8,7,5,2) (11,6,4,1),(10,7,5),(9,8,3,2) (11,6,4,1),(10,7,3,2),(9,8,5) (11,6,3,2),(10,8,4),(9,7,5,1) (11,6,3,2),(10,7,5),(9,8,4,1) (11,6,3,2),(10,7,4,1),(9,8,5)
再问： 大哥，我是要上黑板演讲的，总不能一一列举吧。。。
再答： 这个有很多特例...如果研究算法还是会写一大堆的...至少还要等一定时间才能研究规律... 下面是分2组的 分2组共33种可能 (11,10,9,3),(8,7,6,5,4,2,1) (11,10,9,2,1),(8,7,6,5,4,3) (11,10,8,4),(9,7,6,5,3,2,1) (11,10,8,3,1),(9,7,6,5,4,2) (11,10,7,5),(9,8,6,4,3,2,1) (11,10,7,4,1),(9,8,6,5,3,2) (11,10,7,3,2),(9,8,6,5,4,1) (11,10,6,5,1),(9,8,7,4,3,2) (11,10,6,4,2),(9,8,7,5,3,1) (11,10,6,3,2,1),(9,8,7,5,4) (11,10,5,4,2,1),(9,8,7,6,3) (11,10,5,4,3),(9,8,7,6,2,1) (11,9,8,5),(10,7,6,4,3,2,1) (11,9,8,4,1),(10,7,6,5,3,2) (11,9,8,3,2),(10,7,6,5,4,1) (11,9,7,6),(10,8,5,4,3,2,1) (11,9,7,5,1),(10,8,6,4,3,2) (11,9,7,4,2),(10,8,6,5,3,1) (11,9,7,3,2,1),(10,8,6,5,4) (11,9,6,5,2),(10,8,7,4,3,1) (11,9,6,4,3),(10,8,7,5,2,1) (11,9,6,4,2,1),(10,8,7,5,3) (11,9,5,4,3,1),(10,8,7,6,2) (11,8,7,6,1),(10,9,5,4,3,2) (11,8,7,5,2),(10,9,6,4,3,1) (11,8,7,4,3),(10,9,6,5,2,1) (11,8,7,4,2,1),(10,9,6,5,3) (11,8,6,5,3),(10,9,7,4,2,1) (11,8,6,5,2,1),(10,9,7,4,3) (11,8,6,4,3,1),(10,9,7,5,2) (11,8,5,4,3,2),(10,9,7,6,1) (11,7,6,4,3,2),(10,9,8,5,1) (11,7,5,4,3,2,1),(10,9,8,6) 我现在吧整体思路介绍下 还是会很复杂 如果你还在的话我大致说下 22分解成1到11之间的数的和有45种可能